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Can you do it with just two numbers, like |a+b| <= |a| + |b| ?

Would it be basically the same proof?

Exactly the same, yes.

Can you prove it?

Ok, yeah I have that one from an example in class.

Well then it's the same thing. Think of it like
|(a+b) + c| <= |(a+b)| + |c| <= |a| + |b| + |c|

Oh, that is super easy then, thanks