anonymous
  • anonymous
Prove that if a, b, and c are real numbers, then la+b+cl<=lal+lbl+lcl
Mathematics
chestercat
  • chestercat
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anonymous
  • anonymous
Can you do it with just two numbers, like |a+b| <= |a| + |b| ?
anonymous
  • anonymous
Would it be basically the same proof?
anonymous
  • anonymous
Exactly the same, yes.

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anonymous
  • anonymous
Can you prove it?
anonymous
  • anonymous
Ok, yeah I have that one from an example in class.
anonymous
  • anonymous
Well then it's the same thing. Think of it like |(a+b) + c| <= |(a+b)| + |c| <= |a| + |b| + |c|
anonymous
  • anonymous
Oh, that is super easy then, thanks

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