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dddan
Group Title
if a=2 ; b=5; c=5
how would you solve the quadratic equation?
 2 years ago
 2 years ago
dddan Group Title
if a=2 ; b=5; c=5 how would you solve the quadratic equation?
 2 years ago
 2 years ago

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hartnn Group TitleBest ResponseYou've already chosen the best response.1
then the two roots of x are: \(\huge{x=\frac{b \pm \sqrt{b^24ac}}{2a}}\)
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Use the quadratic foumula \[x_1 =\frac{ b + \sqrt{b^24ac}} {2a}\] \[x_2 =\frac{ b  \sqrt{b^24ac}} {2a}\]
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
ya but i got 4+ the square root of 24 / 4 does this make sense?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
your b=5, how did u get 4+/ ... ?
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
sry the b=4 and the c=5
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
You have imaginary roots. Is that what you're worried about?
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Why? Is it a physics problem and you are supposed to have real roots? Because there is nothing wrong with the quadratic formula. Double check your coefficients
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
u actually have imaginary roots for this..
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
alright can u tell me where to take it from the imaginary roots?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
how did u get square root of 24 ?
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
because with the coefficients, its (4)^24(2)(5) , in the square root right?
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
lol! b=5 not 4
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
no i i mixed up the coefficents in the original question. i was given a=2;b=4;c=5
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
ok, \(\huge{x=\frac{4 \pm \sqrt{24}}{4}}=\frac{4 \pm 2\sqrt{6}}{4}=\frac{2\pm i\sqrt{6}}{2}\)
 2 years ago

dddan Group TitleBest ResponseYou've already chosen the best response.0
alright thank you very much!
 2 years ago
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