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dddan Group Title

how do you solve, x/2+x/5=x/6-1/3

  • one year ago
  • one year ago

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  1. eyust707 Group Title
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    You bring all the terms with x's to one side and the numerical term to the other side. Then you find the least common multiple of the denominators. You multiply each term by the appropriate factor to make the denominators all have the same LCM. Then you add the terms. Finally you multiply each side by the denominator so that x is isolated.

    • one year ago
  2. dddan Group Title
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    can you explain further?

    • one year ago
  3. theEric Group Title
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    Well, you want x to be on only one side of the equation when you're finished, so that's actually a good place to start.

    • one year ago
  4. theEric Group Title
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    Given\[\frac{x}{2}+\frac{x}{5}=\frac{x}{6}-\frac{1}{3}\],

    • one year ago
  5. GeekChic_ Group Title
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    X=5/8???

    • one year ago
  6. dddan Group Title
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    i put all the x values on one side and i made the LCD 60 is that good so far?

    • one year ago
  7. theEric Group Title
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    Correct, GeekChic_! 60 is a good denominator! 30 also works if you'd like, but 60 will be fine too!

    • one year ago
  8. dddan Group Title
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    yea thats what i got but shouldn't it be -5/8?

    • one year ago
  9. dddan Group Title
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    yea lol i meant 30 as LCD

    • one year ago
  10. theEric Group Title
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    So you have\[\frac{30x}{60}+\frac{12x}{60}-\frac{10x}{60}=-\frac{1}{3}\]

    • one year ago
  11. dddan Group Title
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    yup

    • one year ago
  12. theEric Group Title
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    Oh yeah, definately\[-\frac{5}{8}\]

    • one year ago
  13. GeekChic_ Group Title
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    \[\frac{ 5x+2x }{ 10 }=\frac{ 3x-6 }{ 18 }\] then cross-multiply \[18(5x+2x)=10(5x+2x)\]

    • one year ago
  14. GeekChic_ Group Title
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    x=-5/8

    • one year ago
  15. dddan Group Title
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    alright thanks guys!

    • one year ago
  16. theEric Group Title
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    No problem! I'm glad you could work through the problem! Take care!

    • one year ago
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