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anonymous
 3 years ago
how do you solve, x/2+x/5=x/61/3
anonymous
 3 years ago
how do you solve, x/2+x/5=x/61/3

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eyust707
 3 years ago
Best ResponseYou've already chosen the best response.0You bring all the terms with x's to one side and the numerical term to the other side. Then you find the least common multiple of the denominators. You multiply each term by the appropriate factor to make the denominators all have the same LCM. Then you add the terms. Finally you multiply each side by the denominator so that x is isolated.

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0can you explain further?

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Well, you want x to be on only one side of the equation when you're finished, so that's actually a good place to start.

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Given\[\frac{x}{2}+\frac{x}{5}=\frac{x}{6}\frac{1}{3}\],

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i put all the x values on one side and i made the LCD 60 is that good so far?

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Correct, GeekChic_! 60 is a good denominator! 30 also works if you'd like, but 60 will be fine too!

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea thats what i got but shouldn't it be 5/8?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0yea lol i meant 30 as LCD

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0So you have\[\frac{30x}{60}+\frac{12x}{60}\frac{10x}{60}=\frac{1}{3}\]

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0Oh yeah, definately\[\frac{5}{8}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ 5x+2x }{ 10 }=\frac{ 3x6 }{ 18 }\] then crossmultiply \[18(5x+2x)=10(5x+2x)\]

theEric
 3 years ago
Best ResponseYou've already chosen the best response.0No problem! I'm glad you could work through the problem! Take care!
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