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dddan

  • 2 years ago

how do you solve, x/2+x/5=x/6-1/3

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  1. eyust707
    • 2 years ago
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    You bring all the terms with x's to one side and the numerical term to the other side. Then you find the least common multiple of the denominators. You multiply each term by the appropriate factor to make the denominators all have the same LCM. Then you add the terms. Finally you multiply each side by the denominator so that x is isolated.

  2. dddan
    • 2 years ago
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    can you explain further?

  3. theEric
    • 2 years ago
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    Well, you want x to be on only one side of the equation when you're finished, so that's actually a good place to start.

  4. theEric
    • 2 years ago
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    Given\[\frac{x}{2}+\frac{x}{5}=\frac{x}{6}-\frac{1}{3}\],

  5. GeekChic_
    • 2 years ago
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    X=5/8???

  6. dddan
    • 2 years ago
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    i put all the x values on one side and i made the LCD 60 is that good so far?

  7. theEric
    • 2 years ago
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    Correct, GeekChic_! 60 is a good denominator! 30 also works if you'd like, but 60 will be fine too!

  8. dddan
    • 2 years ago
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    yea thats what i got but shouldn't it be -5/8?

  9. dddan
    • 2 years ago
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    yea lol i meant 30 as LCD

  10. theEric
    • 2 years ago
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    So you have\[\frac{30x}{60}+\frac{12x}{60}-\frac{10x}{60}=-\frac{1}{3}\]

  11. dddan
    • 2 years ago
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    yup

  12. theEric
    • 2 years ago
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    Oh yeah, definately\[-\frac{5}{8}\]

  13. GeekChic_
    • 2 years ago
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    \[\frac{ 5x+2x }{ 10 }=\frac{ 3x-6 }{ 18 }\] then cross-multiply \[18(5x+2x)=10(5x+2x)\]

  14. GeekChic_
    • 2 years ago
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    x=-5/8

  15. dddan
    • 2 years ago
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    alright thanks guys!

  16. theEric
    • 2 years ago
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    No problem! I'm glad you could work through the problem! Take care!

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