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anonymous
 4 years ago
Can someone help me solve this....
anonymous
 4 years ago
Can someone help me solve this....

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348871903875:dw If length of this rectangle be thrice its width and its perimeter be 56, then find the co ordinates of the rest of the sides...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Can you use that information to set up the two equations you need?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Ive tried but Im getting two second degree equations!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Actually I'm down with a terrible cold so my brain aint working so well.. So need a lil help!!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Woah. Well, "The length is thrice the width" > L=3W.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"Perimeter is 56" > 2L+2W=56.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yah got that part ryt!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Sub the first equation into the second to solve for W.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0length = 18 units and breadth 6

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.018 and 6 won't get you a perimeter of 56.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ryt!! Sorry!!! 21 and 7!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Excellent. Now you can just count over and down from the given point to find all the other coordinates.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yeah!! But when I try to use the distance formula!!! Im getting two second degree equations!! How m I suppose to solve them when ive got two equation something like ax^2+b^y2+cx+dy+e=0

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I think i made some mistake somewhere. Would you be kind enough to help me out!! Its the darn cold!!

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Forget about the distance formula! Just count.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0The distance formula is so overrated. It is merely the pythagorean theorem, but when you have horizontal and vertical lines, you don't need to solve for a hypotenuse.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0then?? Should I just put in simple increment formula and solve??

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0I know its suppose to be darn simple but my heads all frozen up!! @CliffSedge

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348872917396:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348872954175:dw etc.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0No formulas, no solving  elementary arithmetic.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0k got it!! :D Thank man!!! Thanx a ton!! :P hahahahha!! Ryt!!
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