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robinfr93Best ResponseYou've already chosen the best response.0
dw:1348871903875:dw If length of this rectangle be thrice its width and its perimeter be 56, then find the co ordinates of the rest of the sides...
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Can you use that information to set up the two equations you need?
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Ive tried but Im getting two second degree equations!!!
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
Actually I'm down with a terrible cold so my brain aint working so well.. So need a lil help!!!
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Woah. Well, "The length is thrice the width" > L=3W.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
"Perimeter is 56" > 2L+2W=56.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
yah got that part ryt!!
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Sub the first equation into the second to solve for W.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
length = 18 units and breadth 6
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
18 and 6 won't get you a perimeter of 56.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
ryt!! Sorry!!! 21 and 7!!
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Excellent. Now you can just count over and down from the given point to find all the other coordinates.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
yeah!! But when I try to use the distance formula!!! Im getting two second degree equations!! How m I suppose to solve them when ive got two equation something like ax^2+b^y2+cx+dy+e=0
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I think i made some mistake somewhere. Would you be kind enough to help me out!! Its the darn cold!!
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
Forget about the distance formula! Just count.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
The distance formula is so overrated. It is merely the pythagorean theorem, but when you have horizontal and vertical lines, you don't need to solve for a hypotenuse.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
then?? Should I just put in simple increment formula and solve??
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
I know its suppose to be darn simple but my heads all frozen up!! @CliffSedge
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
dw:1348872917396:dw
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
dw:1348872954175:dw etc.
 one year ago

CliffSedgeBest ResponseYou've already chosen the best response.1
No formulas, no solving  elementary arithmetic.
 one year ago

robinfr93Best ResponseYou've already chosen the best response.0
k got it!! :D Thank man!!! Thanx a ton!! :P hahahahha!! Ryt!!
 one year ago
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