solve the system of linear equations by graphing. [3x+y=0
[2x+y=2

- anonymous

solve the system of linear equations by graphing. [3x+y=0
[2x+y=2

- schrodinger

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- anonymous

get y by its self do u know how to do that?

- anonymous

no

- anonymous

okay well you divide 3x by 0 and what do u get?

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## More answers

- anonymous

0

- anonymous

no for equations like this u just keep it in the equation so what you suppose to get is y=3x+0 and now you have something to graph

- anonymous

no try and do it on the next one

- anonymous

i meant now try*

- anonymous

so is it -3x ?

- anonymous

no where did u get the negative from?

- anonymous

i gave u the answer now all u have to do it graph it

- anonymous

but u still have to get the 2x+y=2 try to do it

- anonymous

I don't know how to graph that

- anonymous

the answer is [y=3x+0
[y=2x+2 you dont know how to graph that?

- anonymous

no

- anonymous

do u know what the y-intercept is?

- anonymous

and the slope?

- anonymous

no

- anonymous

do you know this equation y=mx+b?

- anonymous

m is the slope and b is the y-intercept?

- anonymous

I don't understand :(

- anonymous

is this your homework?

- anonymous

yes

- helder_edwin

u have
\[ \large 3x+y=0\qquad\text{and}\qquad 2x+y=2 \]

- anonymous

ok

- helder_edwin

isolating y u have
\[ \large y=-3x\qquad\text{and}\qquad y=-2x+2 \]
ok?

- anonymous

ok

- helder_edwin

the easiest way to graph lines is doing a table. u need only two points.

- anonymous

ok

- helder_edwin

|dw:1348879936181:dw|

- helder_edwin

|dw:1348879976897:dw|

- anonymous

ok so what is the ordered pair ?

- helder_edwin

for the first line u have the points (0,0) and (1,-3)
for the second (0,2) and (1,0).

- anonymous

ok, so what is the solution of the system of equations ????

- helder_edwin

draw the lines. do it with the outmost precision u can.

- helder_edwin

i can't do it here.
this is something u have to do on your own.

- anonymous

ok, thanks

- helder_edwin

u r welcome

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