solve the system of linear equations by graphing. [3x+y=0 [2x+y=2

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solve the system of linear equations by graphing. [3x+y=0 [2x+y=2

Mathematics
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get y by its self do u know how to do that?
no
okay well you divide 3x by 0 and what do u get?

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0
no for equations like this u just keep it in the equation so what you suppose to get is y=3x+0 and now you have something to graph
no try and do it on the next one
i meant now try*
so is it -3x ?
no where did u get the negative from?
i gave u the answer now all u have to do it graph it
but u still have to get the 2x+y=2 try to do it
I don't know how to graph that
the answer is [y=3x+0 [y=2x+2 you dont know how to graph that?
no
do u know what the y-intercept is?
and the slope?
no
do you know this equation y=mx+b?
m is the slope and b is the y-intercept?
I don't understand :(
is this your homework?
yes
u have \[ \large 3x+y=0\qquad\text{and}\qquad 2x+y=2 \]
ok
isolating y u have \[ \large y=-3x\qquad\text{and}\qquad y=-2x+2 \] ok?
ok
the easiest way to graph lines is doing a table. u need only two points.
ok
|dw:1348879936181:dw|
|dw:1348879976897:dw|
ok so what is the ordered pair ?
for the first line u have the points (0,0) and (1,-3) for the second (0,2) and (1,0).
ok, so what is the solution of the system of equations ????
draw the lines. do it with the outmost precision u can.
i can't do it here. this is something u have to do on your own.
ok, thanks
u r welcome

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