Tresag 3 years ago solve the system of linear equations by graphing. [3x+y=0 [2x+y=2

1. sonja_lee2

get y by its self do u know how to do that?

2. Tresag

no

3. sonja_lee2

okay well you divide 3x by 0 and what do u get?

4. Tresag

0

5. sonja_lee2

no for equations like this u just keep it in the equation so what you suppose to get is y=3x+0 and now you have something to graph

6. sonja_lee2

no try and do it on the next one

7. sonja_lee2

i meant now try*

8. Tresag

so is it -3x ?

9. sonja_lee2

no where did u get the negative from?

10. sonja_lee2

i gave u the answer now all u have to do it graph it

11. sonja_lee2

but u still have to get the 2x+y=2 try to do it

12. Tresag

I don't know how to graph that

13. sonja_lee2

the answer is [y=3x+0 [y=2x+2 you dont know how to graph that?

14. Tresag

no

15. sonja_lee2

do u know what the y-intercept is?

16. sonja_lee2

and the slope?

17. Tresag

no

18. sonja_lee2

do you know this equation y=mx+b?

19. sonja_lee2

m is the slope and b is the y-intercept?

20. Tresag

I don't understand :(

21. sonja_lee2

22. Tresag

yes

23. helder_edwin

u have $\large 3x+y=0\qquad\text{and}\qquad 2x+y=2$

24. Tresag

ok

25. helder_edwin

isolating y u have $\large y=-3x\qquad\text{and}\qquad y=-2x+2$ ok?

26. Tresag

ok

27. helder_edwin

the easiest way to graph lines is doing a table. u need only two points.

28. Tresag

ok

29. helder_edwin

|dw:1348879936181:dw|

30. helder_edwin

|dw:1348879976897:dw|

31. Tresag

ok so what is the ordered pair ?

32. helder_edwin

for the first line u have the points (0,0) and (1,-3) for the second (0,2) and (1,0).

33. Tresag

ok, so what is the solution of the system of equations ????

34. helder_edwin

draw the lines. do it with the outmost precision u can.

35. helder_edwin

i can't do it here. this is something u have to do on your own.

36. Tresag

ok, thanks

37. helder_edwin

u r welcome