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alexray19 Group TitleBest ResponseYou've already chosen the best response.0
Yes, it is a force. But its magnitude, direction, behavior, etc is a function of several other variables related to the nature of the object experiencing the resistance (e.g. its shape, velocity, its environment, the properties of the air, etc).
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
What do you mean? Acceleration has no influence on drag force, so \(\frac{dF_{drag}}{da}=0\) , but it has an influence on the acceleration since it's a force.
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
***Instantaneous acc has no influence on drag
 one year ago

alexray19 Group TitleBest ResponseYou've already chosen the best response.0
Assuming ceteris paribus, as an object travels at a constant velocity in a straight line through nonturbulent air, it experiences a constant acceleration backwards caused by the air.
 one year ago

jk_16 Group TitleBest ResponseYou've already chosen the best response.0
the grap of a vt system under the influence of air resistance..is not a constant v(t)
 one year ago

alexray19 Group TitleBest ResponseYou've already chosen the best response.0
That is, in order to maintain constant velocity, the object must constantly be accelerating forward with a force equal but opposite to the force caused by the air resistance. It's like driving your car at high speeds; you have to constantly give it some gas to maintain your velocity, which is goes against Newton's law that an object in motion remains in motion. The resistance caused by air (and internal friction) accounts for this need to constantly accelerate the car.
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
If an object is ONLY encountering drag, \[F = \frac{1}{2}cAv^2\]\[m a = \frac{1}{2}cAv^2\]\[k=.5cA/m; \frac{d v}{dt}=kv^2\]
 one year ago

jk_16 Group TitleBest ResponseYou've already chosen the best response.0
@vf321 where did you get the initial F=1/2 cAv^2 from
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
That's the formula for drag, if I remember correctly.
 one year ago

jk_16 Group TitleBest ResponseYou've already chosen the best response.0
how do i derive it?
 one year ago

jk_16 Group TitleBest ResponseYou've already chosen the best response.0
F=12cAv2 ma=12cAv2 k=.5cA/m;dvdt=kv2
 one year ago

vf321 Group TitleBest ResponseYou've already chosen the best response.0
Well u just did it...
 one year ago
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