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jpjones Group Title

derivative of (t-1/t)

  • 2 years ago
  • 2 years ago

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  1. vf321 Group Title
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    For t!=0, f(t) = 1-(1/t). Do you know how to derive that?

    • 2 years ago
  2. alexray19 Group Title
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    Do you mean \[\frac{t-1}{t}\] or \[t-\frac{1}{t}\]?

    • 2 years ago
  3. jpjones Group Title
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    the second one

    • 2 years ago
  4. vf321 Group Title
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    Oh nvm forget my answer then.

    • 2 years ago
  5. alexray19 Group Title
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    Well you're just doing two separate derivatives then. One for t, and one for -1/t. Can you do these separately?

    • 2 years ago
  6. jpjones Group Title
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    no i wouldn't have asked othewrwise

    • 2 years ago
  7. jpjones Group Title
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    i think the derivative of t is zero

    • 2 years ago
  8. alexray19 Group Title
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    You don't know what the derivative of t is?

    • 2 years ago
  9. jpjones Group Title
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    or 1

    • 2 years ago
  10. alexray19 Group Title
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    No, 0 is only the derivative of a constant. For example, the derivative of the number 5 is 0. t is a variable that changes, so its derivative can't be 0 (that would imply it's not changing). Yes, 1 is correct for t.

    • 2 years ago
  11. jpjones Group Title
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    now -1/t?

    • 2 years ago
  12. wio Group Title
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    Use to power rule: \[\frac{d}{dx}x^n = n\cdot x^{n-1}\] In the first case, n = 1, and in the second case n = -1.

    • 2 years ago
  13. alexray19 Group Title
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    If you know the power rule, you can use it to derive -1/t by first rewriting it as \[-t^{-1}\]

    • 2 years ago
  14. jpjones Group Title
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    thank wio

    • 2 years ago
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