anonymous
  • anonymous
derivative of (t-1/t)
Mathematics
  • Stacey Warren - Expert brainly.com
Hey! We 've verified this expert answer for you, click below to unlock the details :)
SOLVED
At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga. Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus. Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.
chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
anonymous
  • anonymous
For t!=0, f(t) = 1-(1/t). Do you know how to derive that?
anonymous
  • anonymous
Do you mean \[\frac{t-1}{t}\] or \[t-\frac{1}{t}\]?
anonymous
  • anonymous
the second one

Looking for something else?

Not the answer you are looking for? Search for more explanations.

More answers

anonymous
  • anonymous
Oh nvm forget my answer then.
anonymous
  • anonymous
Well you're just doing two separate derivatives then. One for t, and one for -1/t. Can you do these separately?
anonymous
  • anonymous
no i wouldn't have asked othewrwise
anonymous
  • anonymous
i think the derivative of t is zero
anonymous
  • anonymous
You don't know what the derivative of t is?
anonymous
  • anonymous
or 1
anonymous
  • anonymous
No, 0 is only the derivative of a constant. For example, the derivative of the number 5 is 0. t is a variable that changes, so its derivative can't be 0 (that would imply it's not changing). Yes, 1 is correct for t.
anonymous
  • anonymous
now -1/t?
anonymous
  • anonymous
Use to power rule: \[\frac{d}{dx}x^n = n\cdot x^{n-1}\] In the first case, n = 1, and in the second case n = -1.
anonymous
  • anonymous
If you know the power rule, you can use it to derive -1/t by first rewriting it as \[-t^{-1}\]
anonymous
  • anonymous
thank wio

Looking for something else?

Not the answer you are looking for? Search for more explanations.