Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
Metamath
\[\int_{0}^{\infty} \text{J}_0(a\sqrt{1+x^2}) \ \text{d}x\]
 one year ago
 one year ago
Metamath \[\int_{0}^{\infty} \text{J}_0(a\sqrt{1+x^2}) \ \text{d}x\]
 one year ago
 one year ago

This Question is Closed

sauravshakyaBest ResponseYou've already chosen the best response.0
@mukushla can u PLZ explain me the symbols?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
\(J_0\) is the bessel function of order 0
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
looks like you are up to something!!
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
\[ J_\alpha(x) = \sum_{m=0}^\infty \frac{(1)^m}{m! \, \Gamma(m+\alpha+1)} {\left(\tfrac{1}{2}x\right)}^{2m+\alpha} \] \[ \int_0^\infty \sum_{m=0}^\infty \frac{(1)^m}{m! \, \Gamma(m+1)}\left( {1 \over 2} a \sqrt{ 1 + x^2}\right)^{2m} \\ \]
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
dw:1349011854953:dw
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
this doesn't looks like converging ... let's try some other.
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
For a=1, the numerical value seems to be 0.540302
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
\[\int_{0}^{\infty} \text{J}_0(a\sqrt{1+x^2}) \ \text{d}x=\frac{\cos a}{a}\]
 one year ago

experimentXBest ResponseYou've already chosen the best response.1
how do do that man?
 one year ago

mukushlaBest ResponseYou've already chosen the best response.1
using the formula\[\large J_\lambda(z)=\frac{1}{2\pi i}(\frac{z}{2})^{\lambda} \int_C t^{\lambda+1} e^{t\frac{z^2}{4t}} \text{d}t\]
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.