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mathslover Group Title

What is \[S_n - S_{n-1}\]

  • one year ago
  • one year ago

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  1. jasonxx Group Title
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    \[S= ut +\frac{ 1 }{ 2 }a t^2\] use this and you are done , put t= n and t= n-1

    • one year ago
  2. jasonxx Group Title
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    there will be two equations

    • one year ago
  3. mathslover Group Title
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    right and we get : \[\large{S_n = u + \frac{a(2n-1)}{2}}\]

    • one year ago
  4. mathslover Group Title
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    but can we prove that : \[S_n - S_{n-1}=S_n\] ?

    • one year ago
  5. jasonxx Group Title
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    No because \[S _{n}\] is the distance traveled in nth second and S(n-1) is the distance traveled in (n-1) seconds, how could their difference be equal to distance traveled in n seconds ... think :)

    • one year ago
  6. jasonxx Group Title
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    *n seconds

    • one year ago
  7. jasonxx Group Title
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    not nth

    • one year ago
  8. mathslover Group Title
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    yes very correct but the formula says S_n = u + a(2n-1)/2

    • one year ago
  9. mathslover Group Title
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    Oh! OK, so it is S_nth = u + a(2n-1)/2 ?

    • one year ago
  10. mahmit2012 Group Title
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    |dw:1348928718064:dw|

    • one year ago
  11. jasonxx Group Title
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    @mahmit2012 it's physics i guess

    • one year ago
  12. mathslover Group Title
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    s= displacement, sorry for telling later.

    • one year ago
  13. jasonxx Group Title
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    @mathslover shall i derive the whole equation?

    • one year ago
  14. mathslover Group Title
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    no no I had done that

    • one year ago
  15. mahmit2012 Group Title
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    it is no different.

    • one year ago
  16. jasonxx Group Title
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    okay then where are you stuck?

    • one year ago
  17. mathslover Group Title
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    just confirm me that : \[\large{S_{n^{th}}= u + \frac{a(2n-1)}{2}}\]

    • one year ago
  18. mahmit2012 Group Title
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    for all sequences you can use that.

    • one year ago
  19. jasonxx Group Title
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    yes it is correct

    • one year ago
  20. mathslover Group Title
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    @mahmit2012 how can s_n = a _1 + .... + a_n? I hope you are taking s = displacement and a = acceleration and n = seconds

    • one year ago
  21. mahmit2012 Group Title
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    so if Sn is meant the nth distance for a traveling with constant acceleration you can use it.

    • one year ago
  22. mathslover Group Title
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    Oh, k thanks @jasonxx I was just confused with nth and n seconds. :) Well, now I am interested to learn something new from mahmit2012. I am sure he has a good reaso for his solution

    • one year ago
  23. mathslover Group Title
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    Any example or more explanation @mahmit2012 ?Please?

    • one year ago
  24. jasonxx Group Title
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    @mahmit2012 for all sequence but does it look like that this formula makes a proper sequence ? if a body is accelerated it won't be covering equal distance under under different time interval, still if you think you're right i would love to see that ...and @mathslover you're welcome

    • one year ago
  25. mahmit2012 Group Title
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    |dw:1348929066588:dw|

    • one year ago
  26. mahmit2012 Group Title
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    |dw:1348929143480:dw|

    • one year ago
  27. mathslover Group Title
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    I have no words to say :(

    • one year ago
  28. jasonxx Group Title
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    @mahmit2012 this is what is being done by @mathslover

    • one year ago
  29. mahmit2012 Group Title
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    |dw:1348929260691:dw|

    • one year ago
  30. jasonxx Group Title
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    can distance vary according to a sinusoidial function ??

    • one year ago
  31. mahmit2012 Group Title
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    and so on...you can have many answer for all motions.

    • one year ago
  32. mahmit2012 Group Title
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    yes.

    • one year ago
  33. jasonxx Group Title
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    can distance vary as per the sine rule ? if yes can you give an example i'll be very thankful

    • one year ago
  34. jasonxx Group Title
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    don't mention this body moving on this path |dw:1348929527820:dw|

    • one year ago
  35. mahmit2012 Group Title
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    |dw:1348929615864:dw|

    • one year ago
  36. jasonxx Group Title
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    @mahmit2012 i'll try my best to understand your explanation but i am not sure how the function of distance is in the form of sine, which is traveling on a straight line ..thank you

    • one year ago
  37. jasonxx Group Title
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    and what you've done is just a differentiation of S= A sin wt twice

    • one year ago
  38. jasonxx Group Title
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    @mahmit2012 brother i just need an example of the motion, a real life example and i don't think we need to bring fourier series whilst dealing with kinematics

    • one year ago
  39. mahmit2012 Group Title
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    All motions are related with Forier series. In one dimension or more.

    • one year ago
  40. jasonxx Group Title
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    @demitris i am sure you can elaborate

    • one year ago
  41. mahmit2012 Group Title
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    |dw:1348929928139:dw|

    • one year ago
  42. jasonxx Group Title
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    concept of fourier series looks good whilst dealing with electric current and voltage, i am sure and i agree you have a good point

    • one year ago
  43. mahmit2012 Group Title
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    this is the simplest motion and has just one w. for all motions you can have infinity frequencies.

    • one year ago
  44. jasonxx Group Title
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    @demitris do you agree what @mahmit2012 has said? i'll be thankful if you could help to know further

    • one year ago
  45. jasonxx Group Title
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    @mathslover is bugged lol

    • one year ago
  46. mathslover Group Title
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    No worries, I will catch this with a helicopter soon :) This all is going over my head but still helicopter will catch it for sure ;)

    • one year ago
  47. jasonxx Group Title
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    smile

    • one year ago
  48. jasonxx Group Title
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    well it says, what is the value of the difference of the distance traveled by a body in n seconds and n-1 seconds in context of classical mechanics

    • one year ago
  49. jasonxx Group Title
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    rectilinear

    • one year ago
  50. jasonxx Group Title
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    uniform acceleration

    • one year ago
  51. jasonxx Group Title
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    @demitris i think if i'll keep you providing conditions i am sure it will take way too long and yes u is initial velocity, have mercy please :)

    • one year ago
  52. jasonxx Group Title
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    sure

    • one year ago
  53. jasonxx Group Title
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    okay

    • one year ago
  54. jasonxx Group Title
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    @demitris that has already been done thanks for your work tho

    • one year ago
  55. jasonxx Group Title
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    yes ..but the logic provided by 2mahmit2012 was having some fallacy i asked you to check that out ..but thanks for your concern

    • one year ago
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