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anonymous
 4 years ago
In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?
anonymous
 4 years ago
In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dw:1348935331451:dw

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0"that's probability of senior with flu" whereas they are asking for "probability of person with a flu being a senior" I am not sure if they are same

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0or let event A be senior event B be people with flu A=1/3 S B=.2 S 2/5B=(A ∩ B) probability of people with flu being a senior (A ∩ B)  B

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0well, I thought it was 2/15 but I am having second thoughts

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2you want P(seniorflu) correct?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes, probability of people with flu who are senior

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2\[P(SF)=\frac{P(FS)P(S)}{P(F)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so , P(FS) is what I found to be 2/15?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, also is this a defination \[P(SF)=\frac{P(FS)P(S)}{P(F)}\]

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2\[P(AB)=\frac{P(A\cap B)}{P(B)}\] is the definition of conditional probability

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2use this definition twice to get the formula I have above

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2\[P(AB)=\frac{P(A\cap B)}{P(B)}\] \[P(BA)=\frac{P(A\cap B)}{P(A)}\Rightarrow P(BA)P(A)=P(A\cap B) \] then \[P(AB)=\frac{P(A\cap B)}{P(B)}=\frac{P(BA)P(A)}{P(B)}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0wow, thank you very much

Zarkon
 4 years ago
Best ResponseYou've already chosen the best response.2do you have a new final answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0(2/5)(1/3)  = (1/5) 2/15  = 1/5 2/15 * 5/1=2/3
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