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Libniz
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In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?
 one year ago
 one year ago
Libniz Group Title
In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?
 one year ago
 one year ago

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Libniz Group TitleBest ResponseYou've already chosen the best response.1
here is what I did
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
dw:1348935331451:dw
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
"that's probability of senior with flu" whereas they are asking for "probability of person with a flu being a senior" I am not sure if they are same
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
or let event A be senior event B be people with flu A=1/3 S B=.2 S 2/5B=(A ∩ B) probability of people with flu being a senior (A ∩ B)  B
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
so what is your answer
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
well, I thought it was 2/15 but I am having second thoughts
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
you want P(seniorflu) correct?
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
yes, probability of people with flu who are senior
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P(SF)=\frac{P(FS)P(S)}{P(F)}\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
so , P(FS) is what I found to be 2/15?
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P(FS)=\frac{2}{5}\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
ok, also is this a defination \[P(SF)=\frac{P(FS)P(S)}{P(F)}\]
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P(AB)=\frac{P(A\cap B)}{P(B)}\] is the definition of conditional probability
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
use this definition twice to get the formula I have above
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
\[P(AB)=\frac{P(A\cap B)}{P(B)}\] \[P(BA)=\frac{P(A\cap B)}{P(A)}\Rightarrow P(BA)P(A)=P(A\cap B) \] then \[P(AB)=\frac{P(A\cap B)}{P(B)}=\frac{P(BA)P(A)}{P(B)}\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
wow, thank you very much
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.2
do you have a new final answer?
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.1
(2/5)(1/3)  = (1/5) 2/15  = 1/5 2/15 * 5/1=2/3
 one year ago
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