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In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?
 one year ago
 one year ago
In probabilityland, one third of population is senior. Every winter 20% of population gets the flu. on average, two out of five seniors get the flu. what is the probability that a person with the flu is senior?
 one year ago
 one year ago

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LibnizBest ResponseYou've already chosen the best response.1
"that's probability of senior with flu" whereas they are asking for "probability of person with a flu being a senior" I am not sure if they are same
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
or let event A be senior event B be people with flu A=1/3 S B=.2 S 2/5B=(A ∩ B) probability of people with flu being a senior (A ∩ B)  B
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
well, I thought it was 2/15 but I am having second thoughts
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
you want P(seniorflu) correct?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
yes, probability of people with flu who are senior
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[P(SF)=\frac{P(FS)P(S)}{P(F)}\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
so , P(FS) is what I found to be 2/15?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
ok, also is this a defination \[P(SF)=\frac{P(FS)P(S)}{P(F)}\]
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[P(AB)=\frac{P(A\cap B)}{P(B)}\] is the definition of conditional probability
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
use this definition twice to get the formula I have above
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
\[P(AB)=\frac{P(A\cap B)}{P(B)}\] \[P(BA)=\frac{P(A\cap B)}{P(A)}\Rightarrow P(BA)P(A)=P(A\cap B) \] then \[P(AB)=\frac{P(A\cap B)}{P(B)}=\frac{P(BA)P(A)}{P(B)}\]
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
wow, thank you very much
 one year ago

ZarkonBest ResponseYou've already chosen the best response.2
do you have a new final answer?
 one year ago

LibnizBest ResponseYou've already chosen the best response.1
(2/5)(1/3)  = (1/5) 2/15  = 1/5 2/15 * 5/1=2/3
 one year ago
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