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Libniz
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P(X=1)= P(x=+1)=1/2P(X=0)
a) compute P(X=0)
b)compute Standand deviation funcion of x
c)draw cumulative distributive function of x
d) compute P(x=1 x>=0)
 2 years ago
 2 years ago
Libniz Group Title
P(X=1)= P(x=+1)=1/2P(X=0) a) compute P(X=0) b)compute Standand deviation funcion of x c)draw cumulative distributive function of x d) compute P(x=1 x>=0)
 2 years ago
 2 years ago

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Libniz Group TitleBest ResponseYou've already chosen the best response.0
P[x=1]+P(x=1)+P[x=0]=1 P[x=1]+P[x=1]=P[x=0] 2P[x=0]=1 P[x=0]=0.5 P[x=1]=P[x=1]=.25
 2 years ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Umm that first line is hard to read.
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
b) standard deviations of X E[x]=.25(1)+.25(1)+0(.5)=0 (E[x])^2=0 E[x^2]=.5 var[x]= .50=.5 standard deviation=.5
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
c)dw:1348940632883:dw
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
d) P[x=0]+P[x=1]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
your final answer for b is not correct
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
oh, sqrt[0.5]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
d)\[P(X=1 X\ge0)=\frac{P(X=1,X\ge 0)}{P(X\ge 0)}\]
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 X\ge0)=\frac{P(X=1,X\ge 0)}{P(X\ge 0)}=\frac{P(X=1)}{P(X\ge 0)}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
what does the comma mean P(X=1,X≥0)?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 \text{ and } X\ge0)\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
product of the two then ?
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
no...they are not independent
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 \text{ and } X\ge0)=P(X=1)\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
oh, "and "means it has to satisfy both condition. x=1 is inside x>=0 ; so we choose x=1
 2 years ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[x\ge 0\Rightarrow x\in\{0,1\}\] \[\{1\}\cap\{0,1\}=\{1\}\]
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{P(X=1)}{P(X\ge 0)}\] 0.25  = 1/3 0.75
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
you are truly a great teacher; thanks sir @Zarkon
 2 years ago
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