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Libniz
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P(X=1)= P(x=+1)=1/2P(X=0)
a) compute P(X=0)
b)compute Standand deviation funcion of x
c)draw cumulative distributive function of x
d) compute P(x=1 x>=0)
 one year ago
 one year ago
Libniz Group Title
P(X=1)= P(x=+1)=1/2P(X=0) a) compute P(X=0) b)compute Standand deviation funcion of x c)draw cumulative distributive function of x d) compute P(x=1 x>=0)
 one year ago
 one year ago

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Libniz Group TitleBest ResponseYou've already chosen the best response.0
P[x=1]+P(x=1)+P[x=0]=1 P[x=1]+P[x=1]=P[x=0] 2P[x=0]=1 P[x=0]=0.5 P[x=1]=P[x=1]=.25
 one year ago

wio Group TitleBest ResponseYou've already chosen the best response.0
Umm that first line is hard to read.
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
b) standard deviations of X E[x]=.25(1)+.25(1)+0(.5)=0 (E[x])^2=0 E[x^2]=.5 var[x]= .50=.5 standard deviation=.5
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
c)dw:1348940632883:dw
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
d) P[x=0]+P[x=1]
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
your final answer for b is not correct
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
oh, sqrt[0.5]
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
d)\[P(X=1 X\ge0)=\frac{P(X=1,X\ge 0)}{P(X\ge 0)}\]
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 X\ge0)=\frac{P(X=1,X\ge 0)}{P(X\ge 0)}=\frac{P(X=1)}{P(X\ge 0)}\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
what does the comma mean P(X=1,X≥0)?
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 \text{ and } X\ge0)\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
product of the two then ?
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
no...they are not independent
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[P(X=1 \text{ and } X\ge0)=P(X=1)\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
oh, "and "means it has to satisfy both condition. x=1 is inside x>=0 ; so we choose x=1
 one year ago

Zarkon Group TitleBest ResponseYou've already chosen the best response.1
\[x\ge 0\Rightarrow x\in\{0,1\}\] \[\{1\}\cap\{0,1\}=\{1\}\]
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
\[\frac{P(X=1)}{P(X\ge 0)}\] 0.25  = 1/3 0.75
 one year ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
you are truly a great teacher; thanks sir @Zarkon
 one year ago
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