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ll three a, b, c****

also, if d=0, then as long as atleast one of a, b, or c is non zero then it IS a subspace right?

actually the set u r given is a subspace if and only if d=0.

but why? and does it matter what a, b, and c are?

no.

u have
\[ \large D=\{(x,y,z):ax+by+cz=d\} \]

ohhh okay.

therefore D is a subspace if and only if d=0

so that same idea applies if the question is ax+by=c, for scalars a, b, c ... subspace of R(2) right

yes

that's what u r supposed to get from this two exercises.

*given space*

i hope i was helpful
gotta go

it most definitely was... i hope to see you around again, you have been very helpful. thank you.