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Jusaquikie
 4 years ago
Find the derivative of the function.
y = 5xe^−kx
y'(x) =
Jusaquikie
 4 years ago
Find the derivative of the function. y = 5xe^−kx y'(x) =

This Question is Closed

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0i know to use the chain rule and the product rule but i don't know how to seperate this out properly

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0y is made up of a product function. Thus, 5x and e^(kx) Hence, we are to use the product rule with the above separations

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0the answer has ln in it how do e and ln work together?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0If you differentiate y = e^ax, what do you get?

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0it would be E^ax right?

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0or would it be ae^ax1

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx } = u \frac{ dv }{ dx } + v\frac{ du }{ dx }\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it will give you ae^ax

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0constant letters confuse me more than anything

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Consider them as numbers

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0but moving a to the front of the equason wouldn't i have a 1 on the exponent?

Jusaquikie
 4 years ago
Best ResponseYou've already chosen the best response.0so 5xe^kx is 5x*e^kx so (5)(e^kx)+(5x)(ke^kx) = 5e^kx  5xke^kx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0So \[y=5xe^\left( kx \right)\] \[\frac{ dy }{ dx } = 5x \frac{ d }{ dx }(e^{kx}) + e ^{kx} \frac{ d }{ dx }(5x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx } = 5x(ke ^{kx}) + e ^{kx}(5)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx } = 5kxe ^{kx} + 5e ^{kx}\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0\[\frac{ dy }{ dx } = 5e ^{kx} (kx  1)\]
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