A community for students.
Here's the question you clicked on:
 0 viewing
Jusaquikie
 2 years ago
Find the derivative of the function.
y = 5xe^−kx
y'(x) =
Jusaquikie
 2 years ago
Find the derivative of the function. y = 5xe^−kx y'(x) =

This Question is Closed

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0i know to use the chain rule and the product rule but i don't know how to seperate this out properly

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1y is made up of a product function. Thus, 5x and e^(kx) Hence, we are to use the product rule with the above separations

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0the answer has ln in it how do e and ln work together?

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1If you differentiate y = e^ax, what do you get?

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0it would be E^ax right?

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0or would it be ae^ax1

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy }{ dx } = u \frac{ dv }{ dx } + v\frac{ du }{ dx }\]

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0constant letters confuse me more than anything

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0but moving a to the front of the equason wouldn't i have a 1 on the exponent?

Jusaquikie
 2 years ago
Best ResponseYou've already chosen the best response.0so 5xe^kx is 5x*e^kx so (5)(e^kx)+(5x)(ke^kx) = 5e^kx  5xke^kx

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1So \[y=5xe^\left( kx \right)\] \[\frac{ dy }{ dx } = 5x \frac{ d }{ dx }(e^{kx}) + e ^{kx} \frac{ d }{ dx }(5x)\]

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy }{ dx } = 5x(ke ^{kx}) + e ^{kx}(5)\]

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy }{ dx } = 5kxe ^{kx} + 5e ^{kx}\]

KKJ
 2 years ago
Best ResponseYou've already chosen the best response.1\[\frac{ dy }{ dx } = 5e ^{kx} (kx  1)\]
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.