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Libniz Group TitleBest ResponseYou've already chosen the best response.0
why is it (1+p)^(mr) instead of (p)^(mr)
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
@zarkon, when you come on can you take a look?
 2 years ago

bahrom7893 Group TitleBest ResponseYou've already chosen the best response.0
@satellite73
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
whew i can explain that one (and not embarrass myself) because it is algebra
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
the probability that you decide to buy a ticket and it loses is \(\frac{1p}{2}\) viewing this as bernoulli trials (independent repeated experiments with only two outcome) the the formula is \[P(x=k)=\dbinom{n}{k}p^k(1p)^{nk}\] but in this case \[p=\frac{1p}{2}\] and therefore \[1p=1\frac{1p}{2}=\frac{1+p}{2}\]
 2 years ago

satellite73 Group TitleBest ResponseYou've already chosen the best response.1
i guess what i wrote is silly, i should have made the first \(p\) a \(p^*\) or some other variable
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
I see, all those 'p' were confusing me
 2 years ago

Libniz Group TitleBest ResponseYou've already chosen the best response.0
thanks for your help
 2 years ago
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