A community for students.
Here's the question you clicked on:
 0 viewing
anonymous
 4 years ago
tough probability problem
anonymous
 4 years ago
tough probability problem

This Question is Closed

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0why is it (1+p)^(mr) instead of (p)^(mr)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@zarkon, when you come on can you take a look?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0whew i can explain that one (and not embarrass myself) because it is algebra

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0the probability that you decide to buy a ticket and it loses is \(\frac{1p}{2}\) viewing this as bernoulli trials (independent repeated experiments with only two outcome) the the formula is \[P(x=k)=\dbinom{n}{k}p^k(1p)^{nk}\] but in this case \[p=\frac{1p}{2}\] and therefore \[1p=1\frac{1p}{2}=\frac{1+p}{2}\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i guess what i wrote is silly, i should have made the first \(p\) a \(p^*\) or some other variable

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0I see, all those 'p' were confusing me
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.