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B is the midpoint, so AB and BC are equal pieces that make up AC
this means AB = BC 5x = 3x+4
So then i would solve for x?
yes you would
tell me what you get
I get .5.. but i know thats wrong.. so, 5x = 3x + 4.. u combine like terms.. right?
subtract 3x from both sides
5x = 3x + 4 5x-3x = 3x + 4-3x 2x = 4
divide 2 do both sides.. x = 2
exactly, now use this to find AB
5(2) = 10 :)
you nailed it
Thanks!! :) Can u help me with another question
Thanks!! :)) Four points A, B, C, and D are coplanar, but only two at a time are collinear. Suppose a line is drawn through each pair of points. How many lines can you draw?
Four points A, B, C, and D are coplanar means that all four points lie in the same plane
but only two at a time are collinear means that all 4 points do NOT form a straight line also, it means that there are no 3 points that form a straight line
so we might have something like this |dw:1348964739339:dw|
Here are two pairs of lines |dw:1348964798916:dw|
oops just meant to say "here are a pair of lines"
Here's another pair |dw:1348964855161:dw|
and another pair |dw:1348964897439:dw|
and that's all we can draw because there are no other possible pairs of lines to draw
:) So, there are 4 possible ways?
double that to get 8
4 pairs of lines = 8 lines
Ahh.. i see now. Thanks so much!! ur really smart :) geometry kicks my butt. You make it easy to understand :)
oh wait, i'm counting 3 pairs (not sure where I got 4 pairs) so 3 pairs = 6 lines
I'm glad I do