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can any one help?

yes thank you

what about the converse?

X=2*3 6/3=2
\[x^{2}=36\] 36/3=12

that only gives me evidence

no if x^2 is divisive by 3, then x is divisible by 3

x=n*3
n=1,2,3,4,5,6,7,8...............
x^2=3,36,81,144.......
divide

yes, you just divide and see for yourself
demostration
x=N*3
(N*3)^2 =n^2 * 3^3

excuse me 3^2

3 is a prime number.
u should pay attention to that!!!

Why?

if \(3\mid x^2\) then \(3\mid x\) because 3 is prime.

yw

That is not true helder. 3|15 but 3 does not divide sqrt15

So if x^2 = 15, 3 is a factor of x^2 but not a factor of x

but 15 is not a perfect square!

so why it is x^2 if it is not a perfect square?

x^2 could be 15 or 18 or 21 or 24 or 27 or 12 .

nerver mind.