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RaphaelFilgueiras Group TitleBest ResponseYou've already chosen the best response.1
2i
 one year ago

bthemesandtricks Group TitleBest ResponseYou've already chosen the best response.0
okay how sure are u Raphael??
 one year ago

TheViper Group TitleBest ResponseYou've already chosen the best response.3
Oh yes nice problem \(\sqrt{4}=\sqrt{1}\times\sqrt{4}=\sqrt{1}\times2\) Therefore we take \(\sqrt{1}\) as iota \(i\) Therefore \(\sqrt{4}=2i\)
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
square root of 1 is "i" The definition of the square root of 1 is i, and i^2 ( "i squared") is negative 1.
 one year ago

bthemesandtricks Group TitleBest ResponseYou've already chosen the best response.0
You are a genius @TheViper
 one year ago

JakeV8 Group TitleBest ResponseYou've already chosen the best response.0
I'll second that...
 one year ago
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