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bthemesandtricks
 2 years ago
Best ResponseYou've already chosen the best response.0okay how sure are u Raphael??

TheViper
 2 years ago
Best ResponseYou've already chosen the best response.3Oh yes nice problem \(\sqrt{4}=\sqrt{1}\times\sqrt{4}=\sqrt{1}\times2\) Therefore we take \(\sqrt{1}\) as iota \(i\) Therefore \(\sqrt{4}=2i\)

JakeV8
 2 years ago
Best ResponseYou've already chosen the best response.0square root of 1 is "i" The definition of the square root of 1 is i, and i^2 ( "i squared") is negative 1.

bthemesandtricks
 2 years ago
Best ResponseYou've already chosen the best response.0You are a genius @TheViper
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