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NotTim

  • 2 years ago

An 82 Kg pilot is flying a stunt airplane pulls out of a dive at a constant speed of 540 km/h. What force is applied on the pilot by the plane seat at the lowest point in the pullout?

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  1. NotTim
    • 2 years ago
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    Minimum radius is 3.3*10^2m. The answer is 6.4*10^3 N.

  2. NotTim
    • 2 years ago
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    My initial answer was 5590.909090...N.

  3. wio
    • 2 years ago
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    So what is the formula for centripetal force?

  4. NotTim
    • 2 years ago
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    Fc=mv^2/r

  5. wio
    • 2 years ago
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    And since he is at the bottom of the circle, the centripetal force is in the same direction as the force of gravity. So they are both just added, right?

  6. wio
    • 2 years ago
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    So \(\Large F_{net} = m\frac{v^2}{r}+ma_{gravity}\) We have \(m, v, r, a_{gravity}\) right? So does this get you the correct answer?

  7. NotTim
    • 2 years ago
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    lemme try this one out first. thx for the help and immediate response

  8. NotTim
    • 2 years ago
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    is gravity suppose to be negative?

  9. NotTim
    • 2 years ago
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    @wio

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