At vero eos et accusamus et iusto odio dignissimos ducimus qui blanditiis praesentium voluptatum deleniti atque corrupti quos dolores et quas molestias excepturi sint occaecati cupiditate non provident, similique sunt in culpa qui officia deserunt mollitia animi, id est laborum et dolorum fuga.
Et harum quidem rerum facilis est et expedita distinctio. Nam libero tempore, cum soluta nobis est eligendi optio cumque nihil impedit quo minus id quod maxime placeat facere possimus, omnis voluptas assumenda est, omnis dolor repellendus.
Itaque earum rerum hic tenetur a sapiente delectus, ut aut reiciendis voluptatibus maiores alias consequatur aut perferendis doloribus asperiores repellat.

Get our expert's

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions.

See more answers at brainly.com

Get this expert

answer on brainly

SEE EXPERT ANSWER

Get your **free** account and access **expert** answers to this and **thousands** of other questions

Did you draw a picture yet. i find this really helps.

So let \(t\) be our variable, and it will represent hours.

Let f(t) be the position of ship sailing south, and g(t) be the position ship sailing east.

f(0) = g(2)

then?

I'm interested in the sol'n as well. How did you come up with f(0) = g(2)

I thought it would be one hour

You're right, it's f(0) = g(1)

ChmE, what is your solution?

Okay bii17. What is the anti-derivative of 5?

Yes, what does \(\int5dx\) equal?

we havent discussed it in our class.. no idea

Since distance = speed * time.

5(0) = 2(1) + c => c = -2

So g(t) = 2t-2
Are you following?

|dw:1348982375609:dw|

See where I'm headed ChmE?

No problem, it's a bit complicated but I can try to explain it better if you'd like.

Basically I made the origin the point where they both reach at some point.

I made t=0 when the first boat is at that position.

so the second boat doesn't get into that position until 1 hour later

so since it is moving at 2 knots, it is 2knot-hours behind, giving us that -2 in 2t-2

No!

It is the time at which the distance between the ships isn't changing.

what should we do next?