A community for students. Sign up today!
Here's the question you clicked on:
 0 viewing
 2 years ago
The base diameter and altitude of a right circulAR cone are observed at a certain instant to be 10 and 20 inches respectively. if the lateral area is constant and the base diameter is increasing at a rate of 1 inch per cubic minute, find the rate at ehich the altitude is decreasing
 2 years ago
The base diameter and altitude of a right circulAR cone are observed at a certain instant to be 10 and 20 inches respectively. if the lateral area is constant and the base diameter is increasing at a rate of 1 inch per cubic minute, find the rate at ehich the altitude is decreasing

This Question is Closed

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1hmm yes.. he formula is LA = pi*r*L

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.01 inch per cubic minute .... means what ? i am not understanding ' CUBIC MINUTE'

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1im sory it's 1 inch per minute

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0LA = pi*r*L , and here L is slant height

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1348992383404:dw

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0is it 1/ sqrt(2) inch/ min

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1the answer will be 2.25 in per min @Gowthaman

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0then somewhere i missed, i check once again

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0but now i got .25 inch/min

Gowthaman
 2 years ago
Best ResponseYou've already chosen the best response.0dh/dr =1/2 (from condition of constant LS area) and dr/dt = 1/2 inch/min (given in the problem) dh/dt = dh/dr x dr/dt =  1/2 x 1/2 =  1/4 = 0.25 inch / min

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1348995046484:dwdw:1348995119250:dwdw:1348995143495:dw

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2dw:1348995200114:dw

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2I hope u can solve it from here...

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1@sauravshakya hey stil there?

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1@sauravshakya what is that?? i didnt understand those with circle..

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2That is radius of the cone

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.2ALSO,dw:1349001642850:dw

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1@hartnn can u help me in this question?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0which part of saurav's explanation did u not understand?

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1here.. dw:1349002226151:dw i used it but i didnt get the correct answer the answer should be 2.25 @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0@bii17 i did get it as 2.25. l^2=425, r=5, h=20, dr/dt=2

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349002789725:dw i get is 8 @hartnn

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0oh sorry, dr/dt = 1/2 and not 2

bii17
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349002976588:dw my answer is 2.. :( @hartnn can u show me what u did?

hartnn
 2 years ago
Best ResponseYou've already chosen the best response.0did u get that u missed the *minus* sign in the beginning ?
Ask your own question
Ask a QuestionFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.