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akash123
 2 years ago
Best ResponseYou've already chosen the best response.3sin(AB)/ cosA*cosB =1/x from Tan A  tan B=x

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3and sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x tanA*tanB= x/y

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0@akash123 sin(AB)/ cosA*cosB =x from Tan A  tan B=x

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3cot(AB) = [ cot A* cot B+1] / ( cot B  cot A)

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3yes...thanks...I have corrected it later

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x divide 2nd by 1st then u'll get tanA*tanB= x/y

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3now use the identity cot(AB) = [ cot A* cot B+1] / ( cot B  cot A) and substitute the value of cot A* cot B and (cot B cot A) then u'll get the answer

akash123
 2 years ago
Best ResponseYou've already chosen the best response.3another way @sauravshakya write the reciprocal f 1st and 2nd equation and add both then simplify it.

sauravshakya
 2 years ago
Best ResponseYou've already chosen the best response.0Yep... I would go with that....

ashna
 2 years ago
Best ResponseYou've already chosen the best response.0okay got it :) thank you !
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