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If tan A  tan B = x and cot B  cot A =Y , pt COT (ab) = 1/X + 1/Y
 one year ago
 one year ago
If tan A  tan B = x and cot B  cot A =Y , pt COT (ab) = 1/X + 1/Y
 one year ago
 one year ago

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akash123Best ResponseYou've already chosen the best response.3
sin(AB)/ cosA*cosB =1/x from Tan A  tan B=x
 one year ago

akash123Best ResponseYou've already chosen the best response.3
and sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x tanA*tanB= x/y
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
@akash123 sin(AB)/ cosA*cosB =x from Tan A  tan B=x
 one year ago

akash123Best ResponseYou've already chosen the best response.3
cot(AB) = [ cot A* cot B+1] / ( cot B  cot A)
 one year ago

akash123Best ResponseYou've already chosen the best response.3
yes...thanks...I have corrected it later
 one year ago

akash123Best ResponseYou've already chosen the best response.3
sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x divide 2nd by 1st then u'll get tanA*tanB= x/y
 one year ago

akash123Best ResponseYou've already chosen the best response.3
now use the identity cot(AB) = [ cot A* cot B+1] / ( cot B  cot A) and substitute the value of cot A* cot B and (cot B cot A) then u'll get the answer
 one year ago

akash123Best ResponseYou've already chosen the best response.3
another way @sauravshakya write the reciprocal f 1st and 2nd equation and add both then simplify it.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.0
Yep... I would go with that....
 one year ago

ashnaBest ResponseYou've already chosen the best response.0
okay got it :) thank you !
 one year ago
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