ashna
If tan A - tan B = x and cot B - cot A =Y , pt COT (a-b) = 1/X + 1/Y
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ashna
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@akash123
akash123
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sin(A-B)/ cosA*cosB =1/x from Tan A - tan B=x
ashna
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okay !
ashna
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then ?
akash123
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and sin(A-B)/ sinA* SinB=y from cotB- cotA =y
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x
tanA*tanB= x/y
sauravshakya
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@akash123
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x
akash123
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cot(A-B) = [ cot A* cot B+1] / ( cot B - cot A)
akash123
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yes...thanks...I have corrected it later
akash123
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sin(A-B)/ sinA* SinB=y from cotB- cotA =y
sin(A-B)/ cosA*cosB =x from Tan A - tan B=x
divide 2nd by 1st
then u'll get
tanA*tanB= x/y
ashna
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yes i understood that !
akash123
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now use the identity
cot(A-B) = [ cot A* cot B+1] / ( cot B - cot A)
and substitute the value of cot A* cot B and (cot B- cot A)
then u'll get the answer
akash123
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another way @sauravshakya
write the reciprocal f 1st and 2nd equation and add both
then simplify it.
sauravshakya
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Yep... I would go with that....
ashna
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okay got it :)
thank you !
akash123
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:)