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anonymous
 4 years ago
If tan A  tan B = x and cot B  cot A =Y , pt COT (ab) = 1/X + 1/Y
anonymous
 4 years ago
If tan A  tan B = x and cot B  cot A =Y , pt COT (ab) = 1/X + 1/Y

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin(AB)/ cosA*cosB =1/x from Tan A  tan B=x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0and sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x tanA*tanB= x/y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0@akash123 sin(AB)/ cosA*cosB =x from Tan A  tan B=x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0cot(AB) = [ cot A* cot B+1] / ( cot B  cot A)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes...thanks...I have corrected it later

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sin(AB)/ sinA* SinB=y from cotB cotA =y sin(AB)/ cosA*cosB =x from Tan A  tan B=x divide 2nd by 1st then u'll get tanA*tanB= x/y

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0yes i understood that !

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0now use the identity cot(AB) = [ cot A* cot B+1] / ( cot B  cot A) and substitute the value of cot A* cot B and (cot B cot A) then u'll get the answer

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0another way @sauravshakya write the reciprocal f 1st and 2nd equation and add both then simplify it.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0Yep... I would go with that....

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay got it :) thank you !
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