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|dw:1349004422200:dw|

|dw:1349004500723:dw|

I need a solution :)

which direction is the trick moving, it is not clear

|dw:1349004602933:dw|

|dw:1349004739213:dw|

|dw:1349004667017:dw|

|dw:1349004778629:dw|

dx/dt =2 feet per second
y is constant..... now, can u find dh/dt

how?

|dw:1349004927462:dw|

Since y is constant dy/dt=0 right?

yes. then?

|dw:1349005061647:dw|

Now, given x=8

y=18-3=15

So, |dw:1349005186713:dw|

right?

@sauravshakya the answer is 16/ 17

Use of calculus is good

|dw:1349005396208:dw|

Now we need to find dl/dt

how to fnd it @sauravshakya

you need a better diagram

|dw:1349005616181:dw||dw:1349005671316:dw|

Did I did some algebra wrong or what???????

hmm i dont know.. the answer should be 16/ 17

|dw:1349005592570:dw|

its ok

its correct

@sauravshakya yes im sure. that is the answer given in the book

But I got 16/15 @goformit100

i did the calculation @sauravshakya is correct now

@ganeshie8 if u r free PLZ see this

@Callisto check it

plz

oh i will do it again

|dw:1349007585718:dw|

15 ^2 + x^2 = (33- y)^2

|dw:1349007886322:dw|
@sauravshakya

did you get 16/17?

that still doesn't give answer.....

Yep

8 / ( 33 - 16 ) * 2 = 16/17 ,
x = 8 , that is given, y = 16 by plugging in
15^2 + x^2 = (33-y)^2

the only weird part is the negative sign

oh nevermind, it should be plus

15^2 + x^2 = (33+y)^2

|dw:1349008213306:dw|

|dw:1349008265370:dw|

So,|dw:1349008256578:dw|

yes it does, u did it @sauravshakya ! :)

yes that is simpler. the trick is to see that y is constant

|dw:1349008430327:dw|

y = 15,

wait, dh/dt is the rate at which the rope is being pulled

so dh/dt = the rate at which the weight is moving up ? interesting