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bii17
 3 years ago
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
bii17
 3 years ago
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?

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goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349004500723:dw

perl
 3 years ago
Best ResponseYou've already chosen the best response.0which direction is the trick moving, it is not clear

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349004602933:dw

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0dw:1349004739213:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349004667017:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349004778629:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dx/dt =2 feet per second y is constant..... now, can u find dh/dt

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349004927462:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3Since y is constant dy/dt=0 right?

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349005061647:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3So, dw:1349005186713:dw

bii17
 3 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya the answer is 16/ 17

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0Use of calculus is good

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349005396208:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3Now we need to find dl/dt

bii17
 3 years ago
Best ResponseYou've already chosen the best response.0how to fnd it @sauravshakya

perl
 3 years ago
Best ResponseYou've already chosen the best response.0A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349005616181:dwdw:1349005671316:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3Did I did some algebra wrong or what???????

bii17
 3 years ago
Best ResponseYou've already chosen the best response.0hmm i dont know.. the answer should be 16/ 17

perl
 3 years ago
Best ResponseYou've already chosen the best response.0x is the distance the weight has been raised, and y is the horizontal distance, where the rope is attached, to the vertical line passing through the pulley.

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3@bii17 u sure the answer is 16/17

bii17
 3 years ago
Best ResponseYou've already chosen the best response.0@sauravshakya yes im sure. that is the answer given in the book

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3But I got 16/15 @goformit100

goformit100
 3 years ago
Best ResponseYou've already chosen the best response.0i did the calculation @sauravshakya is correct now

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3@ganeshie8 if u r free PLZ see this

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3@hartnn can U plz check it

perl
 3 years ago
Best ResponseYou've already chosen the best response.0y is the height that the weight rises from the ground. , x is the distance the truck has moved to the left

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1349007886322:dw @sauravshakya

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3Oh ya....... @hartnn

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1that still doesn't give answer.....

perl
 3 years ago
Best ResponseYou've already chosen the best response.015 ^2 + x^2 = (33 y)^2 2x *dx/dt = 2 ( 33  y) * (dy/dt) x * dx/dt = (33y) * (dy/dt) x/ (33y) * dx/dt = dy/dt , this works

perl
 3 years ago
Best ResponseYou've already chosen the best response.08 / ( 33  16 ) * 2 = 16/17 , x = 8 , that is given, y = 16 by plugging in 15^2 + x^2 = (33y)^2

perl
 3 years ago
Best ResponseYou've already chosen the best response.0the only weird part is the negative sign

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3@hartnn that gives the answer

perl
 3 years ago
Best ResponseYou've already chosen the best response.0oh nevermind, it should be plus

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3dw:1349008213306:dw

sauravshakya
 3 years ago
Best ResponseYou've already chosen the best response.3So,dw:1349008256578:dw

hartnn
 3 years ago
Best ResponseYou've already chosen the best response.1yes it does, u did it @sauravshakya ! :)

perl
 3 years ago
Best ResponseYou've already chosen the best response.0yes that is simpler. the trick is to see that y is constant

perl
 3 years ago
Best ResponseYou've already chosen the best response.0wait, dh/dt is the rate at which the rope is being pulled

perl
 3 years ago
Best ResponseYou've already chosen the best response.0so dh/dt = the rate at which the weight is moving up ? interesting
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