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bii17
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A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 2 years ago
 2 years ago
bii17 Group Title
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 2 years ago
 2 years ago

This Question is Closed

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1349004422200:dw
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349004500723:dw
 2 years ago

bii17 Group TitleBest ResponseYou've already chosen the best response.0
I need a solution :)
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
which direction is the trick moving, it is not clear
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349004602933:dw
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
dw:1349004739213:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349004667017:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349004778629:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dx/dt =2 feet per second y is constant..... now, can u find dh/dt
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349004927462:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Since y is constant dy/dt=0 right?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349005061647:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Now, given x=8
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
y=183=15
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
So, dw:1349005186713:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
right?
 2 years ago

bii17 Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya the answer is 16/ 17
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
Use of calculus is good
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349005396208:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Now we need to find dl/dt
 2 years ago

bii17 Group TitleBest ResponseYou've already chosen the best response.0
how to fnd it @sauravshakya
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
you need a better diagram
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349005616181:dwdw:1349005671316:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Did I did some algebra wrong or what???????
 2 years ago

bii17 Group TitleBest ResponseYou've already chosen the best response.0
hmm i dont know.. the answer should be 16/ 17
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1349005592570:dw
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
x is the distance the weight has been raised, and y is the horizontal distance, where the rope is attached, to the vertical line passing through the pulley.
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
@bii17 u sure the answer is 16/17
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
its correct
 2 years ago

bii17 Group TitleBest ResponseYou've already chosen the best response.0
@sauravshakya yes im sure. that is the answer given in the book
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
But I got 16/15 @goformit100
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
i did the calculation @sauravshakya is correct now
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
@ganeshie8 if u r free PLZ see this
 2 years ago

goformit100 Group TitleBest ResponseYou've already chosen the best response.0
@Callisto check it
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
@hartnn can U plz check it
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
oh i will do it again
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1349007585718:dw
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
15 ^2 + x^2 = (33 y)^2
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
y is the height that the weight rises from the ground. , x is the distance the truck has moved to the left
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
dw:1349007886322:dw @sauravshakya
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
did you get 16/17?
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
Oh ya....... @hartnn
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
that still doesn't give answer.....
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
15 ^2 + x^2 = (33 y)^2 2x *dx/dt = 2 ( 33  y) * (dy/dt) x * dx/dt = (33y) * (dy/dt) x/ (33y) * dx/dt = dy/dt , this works
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
8 / ( 33  16 ) * 2 = 16/17 , x = 8 , that is given, y = 16 by plugging in 15^2 + x^2 = (33y)^2
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
the only weird part is the negative sign
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
@hartnn that gives the answer
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
oh nevermind, it should be plus
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
15^2 + x^2 = (33+y)^2
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
dw:1349008213306:dw
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1349008265370:dw
 2 years ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.3
So,dw:1349008256578:dw
 2 years ago

hartnn Group TitleBest ResponseYou've already chosen the best response.1
yes it does, u did it @sauravshakya ! :)
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
yes that is simpler. the trick is to see that y is constant
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
dw:1349008430327:dw
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
wait, dh/dt is the rate at which the rope is being pulled
 2 years ago

perl Group TitleBest ResponseYou've already chosen the best response.0
so dh/dt = the rate at which the weight is moving up ? interesting
 2 years ago
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