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A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 one year ago
 one year ago
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 one year ago
 one year ago

This Question is Closed

goformit100Best ResponseYou've already chosen the best response.0
dw:1349004500723:dw
 one year ago

perlBest ResponseYou've already chosen the best response.0
which direction is the trick moving, it is not clear
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349004602933:dw
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
dw:1349004739213:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349004667017:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349004778629:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dx/dt =2 feet per second y is constant..... now, can u find dh/dt
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349004927462:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Since y is constant dy/dt=0 right?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349005061647:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
So, dw:1349005186713:dw
 one year ago

bii17Best ResponseYou've already chosen the best response.0
@sauravshakya the answer is 16/ 17
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
Use of calculus is good
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349005396208:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Now we need to find dl/dt
 one year ago

bii17Best ResponseYou've already chosen the best response.0
how to fnd it @sauravshakya
 one year ago

perlBest ResponseYou've already chosen the best response.0
you need a better diagram
 one year ago

perlBest ResponseYou've already chosen the best response.0
A weight is attached to one end of a 33 foot rope which passes over a pulley 18 feet above the ground. the other end is attached to a truck at a point 3 feet above the ground. if the truck moves away at a rate of 2 feet per second, how fast is the weight rising when the truck is 8 feet from the spot directly under the pulley?
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349005616181:dwdw:1349005671316:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Did I did some algebra wrong or what???????
 one year ago

bii17Best ResponseYou've already chosen the best response.0
hmm i dont know.. the answer should be 16/ 17
 one year ago

perlBest ResponseYou've already chosen the best response.0
x is the distance the weight has been raised, and y is the horizontal distance, where the rope is attached, to the vertical line passing through the pulley.
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
@bii17 u sure the answer is 16/17
 one year ago

bii17Best ResponseYou've already chosen the best response.0
@sauravshakya yes im sure. that is the answer given in the book
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
But I got 16/15 @goformit100
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
i did the calculation @sauravshakya is correct now
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
@ganeshie8 if u r free PLZ see this
 one year ago

goformit100Best ResponseYou've already chosen the best response.0
@Callisto check it
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
@hartnn can U plz check it
 one year ago

perlBest ResponseYou've already chosen the best response.0
y is the height that the weight rises from the ground. , x is the distance the truck has moved to the left
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
dw:1349007886322:dw @sauravshakya
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
Oh ya....... @hartnn
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
that still doesn't give answer.....
 one year ago

perlBest ResponseYou've already chosen the best response.0
15 ^2 + x^2 = (33 y)^2 2x *dx/dt = 2 ( 33  y) * (dy/dt) x * dx/dt = (33y) * (dy/dt) x/ (33y) * dx/dt = dy/dt , this works
 one year ago

perlBest ResponseYou've already chosen the best response.0
8 / ( 33  16 ) * 2 = 16/17 , x = 8 , that is given, y = 16 by plugging in 15^2 + x^2 = (33y)^2
 one year ago

perlBest ResponseYou've already chosen the best response.0
the only weird part is the negative sign
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
@hartnn that gives the answer
 one year ago

perlBest ResponseYou've already chosen the best response.0
oh nevermind, it should be plus
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
dw:1349008213306:dw
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.3
So,dw:1349008256578:dw
 one year ago

hartnnBest ResponseYou've already chosen the best response.1
yes it does, u did it @sauravshakya ! :)
 one year ago

perlBest ResponseYou've already chosen the best response.0
yes that is simpler. the trick is to see that y is constant
 one year ago

perlBest ResponseYou've already chosen the best response.0
wait, dh/dt is the rate at which the rope is being pulled
 one year ago

perlBest ResponseYou've already chosen the best response.0
so dh/dt = the rate at which the weight is moving up ? interesting
 one year ago
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