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bigcat Group Title

find the derivative of f(x)=x^2 + x -3 using the definition of the derivative

  • 2 years ago
  • 2 years ago

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  1. Callisto Group Title
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    \[f'(x)\]\[=\lim_{h \rightarrow 0}\frac{f(x+h) - f(x)}{h}\]\[=\lim_{h \rightarrow 0}\frac{[(x+h)^2 + (x+h) -3] -(x^2 + x -3)}{h}\]Can you simplify the fraction first?

    • 2 years ago
  2. bigcat Group Title
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    I used x^2 + 2(x)(h) + h^2 + x +h -3 -x^2 -x +3 = 2x + x ??

    • 2 years ago
  3. Callisto Group Title
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    x^2 + 2(x)(h) + h^2 + x +h -3 -x^2 -x +3 <- correct for denominator. But it's not equal to 2x + x... \[x^2 + 2(x)(h) + h^2 + x +h -3 -x^2 -x +3\]Group the like terms together: \[x^2 -x^2 + x -x -3 +3+ h^2+ 2(x)(h)+h\] Now, can you simplify the above expression

    • 2 years ago
  4. bigcat Group Title
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    basically factor out the h and H(h+2x+1) divided by the h on denominator and = h + 2x + 1?

    • 2 years ago
  5. Callisto Group Title
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    Yes.

    • 2 years ago
  6. Callisto Group Title
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    And you got: \[\lim_{h \rightarrow 0} (h+2x+1)\]Can you evaluate the limit?

    • 2 years ago
  7. bigcat Group Title
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    Would be 2x + 1 ??? Because h is going to 0

    • 2 years ago
  8. Callisto Group Title
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    Indeed it is!

    • 2 years ago
  9. bigcat Group Title
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    Holy Cow! It came together finally!! Thank you very much for your help! I would have been stuck!!!

    • 2 years ago
  10. Callisto Group Title
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    You're welcome :)

    • 2 years ago
  11. bigcat Group Title
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    Have a great day!!

    • 2 years ago
  12. Callisto Group Title
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    You too! :)

    • 2 years ago
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