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Solmyr Group Title

Consider the functions f(x) = x2 − 13 and g(x) = x + 5. What is the value of (f + g)(3)? −4 4 −32 8

  • one year ago
  • one year ago

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  1. amorfide Group Title
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    f(3) + g(3) substitute x=3 into the function f then substitute 3 into the function g then add the answers together

    • one year ago
  2. hartnn Group Title
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    what di u get?

    • one year ago
  3. Solmyr Group Title
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    idk i dont understand how to do these

    • one year ago
  4. hartnn Group Title
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    u know how to find f(3) ?

    • one year ago
  5. Solmyr Group Title
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    nope

    • one year ago
  6. Solmyr Group Title
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    its been a while since i did these and i forgot

    • one year ago
  7. amorfide Group Title
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    f(x) is a function containing x if you want f(3) you want a function containing 3's so wherever x was originally you would replace them all with 3

    • one year ago
  8. hartnn Group Title
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    to get f(3) put x=3 in f(x)

    • one year ago
  9. amorfide Group Title
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    so for your function f(x) = x2 − 13 you want to replace all x with 3 so you get f(3)=3²-13 then do the same with g then add your answers

    • one year ago
  10. Solmyr Group Title
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    f(2) = (2)2 - 13 and g(2) = 2 + 5?

    • one year ago
  11. Solmyr Group Title
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    i mean three lol

    • one year ago
  12. Solmyr Group Title
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    f(3) = (3)2 - 13 and g(3) = 3 + 5?

    • one year ago
  13. amorfide Group Title
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    yes that is right

    • one year ago
  14. amorfide Group Title
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    now get an answer for each function add your answers together

    • one year ago
  15. Solmyr Group Title
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    f(3) = 9 - 13 = f(3) = -4

    • one year ago
  16. Solmyr Group Title
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    g(3) = 3 + 5 = g(3) = 8

    • one year ago
  17. Solmyr Group Title
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    now what do i do???

    • one year ago
  18. amorfide Group Title
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    f+g -4+8

    • one year ago
  19. Solmyr Group Title
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    wait when i do f+g what do i do with the 3's??

    • one year ago
  20. Solmyr Group Title
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    -4+8=4

    • one year ago
  21. Solmyr Group Title
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    so the answer is 4??

    • one year ago
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