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49/98 = 4/8 could be a mathematical fallacy

but i can prove it

don't post answer ... i just need explanation
http://projecteuler.net/problem=33

|dw:1349020445163:dw| don't get irked please :)

Woops!!

lol

funny!!

i guess i understand what i means!!

@experimentX can you please elaborate last line of your question?

this isn't my question if it were mine i would have already solved it.

i didn't expect the nine would be cancelled to give right answer.

i know :)

9*9*9 possibilities ... if you get out trivial case ... 9*9*9 - 10 possible cases.

told ya .. don't post answer. this is supposed to be challenge Q.

programming challenge ..

well the answer is equal to = 2*5*4*2 and another example is 40/80

\[\frac{ 30 }{ 50 },\frac{ 48 }{ 98 }, \frac{ 16 }{ 64 }, \frac{ 40 }{ 80 }\]

zeros are trivial cases.

sorry forgot that

Yep .. got'em all

??

@experimentX what are those? i just got two

yep .. thanks for idea. looks like i hit jackpot. well ... the answers are
16 64
19 95
26 65
49 98

no

@experimentX 26/65 seems in correct

they are multiples of 13

exactly ..i was in haste ...nice you've got the jack pot ..cool