Can anyone explain this to me?
The fraction 49/98 is a curious fraction, as an inexperienced mathematician in attempting to simplify it may incorrectly believe that 49/98 = 4/8, which is correct, is obtained by cancelling the 9s.
We shall consider fractions like, 30/50 = 3/5, to be trivial examples.
There are exactly four non-trivial examples of this type of fraction, less than one in value, and containing two digits in the numerator and denominator.
If the product of these four fractions is given in its lowest common terms, find the value of the denominator.

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- ghazi

49/98 = 4/8 could be a mathematical fallacy

- ghazi

but i can prove it

- experimentX

don't post answer ... i just need explanation
http://projecteuler.net/problem=33

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## More answers

- ghazi

|dw:1349020445163:dw| don't get irked please :)

- experimentX

Woops!!

- ghazi

lol

- experimentX

funny!!

- experimentX

i guess i understand what i means!!

- ghazi

@experimentX can you please elaborate last line of your question?

- experimentX

this isn't my question if it were mine i would have already solved it.

- experimentX

i didn't expect the nine would be cancelled to give right answer.

- ghazi

i know :)

- ghazi

but in the example 30/50 cancel out zeroes you're gonna get that you're lookin for..sorry, let me try this

- experimentX

9*9*9 possibilities ... if you get out trivial case ... 9*9*9 - 10 possible cases.

- ghazi

no, i think there are exactly 4 possibilities and if they are expressed as lowest fraction you'll have denominator of it will be equal to ?? the other example is 16/64

- experimentX

told ya .. don't post answer. this is supposed to be challenge Q.

- experimentX

programming challenge ..

- ghazi

well the answer is equal to = 2*5*4*2 and another example is 40/80

- ghazi

\[\frac{ 30 }{ 50 },\frac{ 48 }{ 98 }, \frac{ 16 }{ 64 }, \frac{ 40 }{ 80 }\]

- experimentX

zeros are trivial cases.

- ghazi

sorry forgot that

- experimentX

Yep .. got'em all

- ghazi

??

- ghazi

@experimentX what are those? i just got two

- anonymous

there are 4 equation to solve\[\frac{ab}{cb}=\frac{a}{c}\]\[\frac{ba}{cb}=\frac{a}{c}\]\[\frac{ba}{bc}=\frac{a}{c}\]\[\frac{ab}{bc}=\frac{a}{c}\]if u wanna do it by hand of course :) these are easy to solve i think

- experimentX

yep .. thanks for idea. looks like i hit jackpot. well ... the answers are
16 64
19 95
26 65
49 98

- ghazi

no

- ghazi

@experimentX 26/65 seems in correct

- experimentX

they are multiples of 13

- ghazi

exactly ..i was in haste ...nice you've got the jack pot ..cool

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