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sum up all the time intervals to get the total time elapsed :)

wait, so first i'll get the delta when t=10?

delta y*

you need to keep track of all the heights and speeds along the way to keep track of the time

aside from that, we are told that at 10 seconds they open their chute and alter the equation

hmmm, my second setup tho is not accounting for the change in accleration is it

so acceleration in the second one is not gravity; but rather the 6 m/s^2

for the equation of delta t, what value of v will i use?

the velocity is stated as 6m/s for the final stage

ah, ok got it. thanks a lot!!!!!!!!!!!!!!!!!

your directions aren't consistent @amistre64

lol, my thoughts arent consistent either :)

for deacceleration stage a is + ; Vi is - ; Vf is - ;

yeah, i still had reservations about that.

so v=-6 instead of 6 in that case

yep

it's deceleration, and it's opposite to the initial direction of motion, then why is a +?

because motion is down? and you already called 'down' negative in earlier equations?

ah, yeah. thnx

np:)

y(17)=y(15) that is

you forgot to include the initial height of 945 meters that it starts at

ugh .... misread the post lol

-6 = 6t -96
-6 + 96 = 6t
90 = 6t
90/6 = t = 15

so i will add the time intervals 10, 15 and ?

10 + 15 + ....
v = d/t
t = d/v ; t = 180/6

w8, isn't the v negative? sorry, jst confused....

ah, ok. got it. thanks @amistre64 and @Algebraic!

youre welcome :)