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solve means, do u need to find roots of that equation ? or just simplify?
So this is what we have: |dw:1349025945871:dw| How many times does x^2 go into x^4?
Let's try to walk him through so he can get the answer. :)
The drawing would be a good tool to walk him through.
Yes so we have |dw:1349026268486:dw|
Now take that number on top (the x^2) and multiply it to your divisor Put the result under the dividend
We are going to subtract that mess Do -(that result when you multiply x^2 and x^2+4)
Since 0x^3 and -4x^2 aren't like terms I moved the 4x^2 inside the parenthesis |dw:1349026566063:dw|
Do that subtraction first then we will put another number on top of that bar
Great! Now x^2 goes into x^3 how many times?
Yep. That goes on top of that bar.
Then you do the same process again
Multiply x and (x^2+4) Put the result under x^3+3x^2 Then subtract
oh its -9x ?
-4x should be in that circle because you have that - outside the parenthesis
oh yeah we need to bring down that other stuff :) great job @Muffinlover
Ok! We will have to bring down that 3 as well later
So how many times does x^2 go into 3x^2 ?
I will show you what I'm looking at it in your drawing: |dw:1349027587423:dw|
well what is 3x^2/x^2 is another way of saying it? or since the x^2's cancel then what is 3/1?
So we put +3 on top of that bar and do what afterwards?
don't forget to do 3(4) too
omg wait! lol.
You remember this step? |dw:1349028682678:dw|
That is 0x^3 not 1x^3
We made this problem longer. My bad. I didn't catch it earlier.