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clarkexo

  • 3 years ago

solve: a^2 · a^3 · a^-4

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  1. clarkexo
    • 3 years ago
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    do you know the answer?

  2. tamtoan
    • 3 years ago
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    use these formula ..a^-n = 1/a^n , a^n . a^m = a^(n+m) and a^n/a^m = a^(n-m) and you can get the answer quick

  3. clarkexo
    • 3 years ago
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    it's not a^9 though..

  4. tamtoan
    • 3 years ago
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    ofcourse it's not, one of the power is negative...check that again :)

  5. clarkexo
    • 3 years ago
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    see that's what confuses me, but I thought when you flip the exponent to make it positive, you add it as a positive exponent?

  6. clarkexo
    • 3 years ago
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    would it be a^1?

  7. tamtoan
    • 3 years ago
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    correct

  8. clarkexo
    • 3 years ago
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    okay, So you're not supposed to flip it then? :S

  9. tamtoan
    • 3 years ago
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    it's two positive powers 2 and 3..you add..one negative power 4 ..you subtract

  10. clarkexo
    • 3 years ago
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    ty

  11. tamtoan
    • 3 years ago
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    yw :)

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