clarkexo
solve: a^2 · a^3 · a^4



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clarkexo
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do you know the answer?

tamtoan
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use these formula ..a^n = 1/a^n , a^n . a^m = a^(n+m) and a^n/a^m = a^(nm)
and you can get the answer quick

clarkexo
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it's not a^9 though..

tamtoan
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ofcourse it's not, one of the power is negative...check that again :)

clarkexo
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see that's what confuses me, but I thought when you flip the exponent to make it positive, you add it as a positive exponent?

clarkexo
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would it be a^1?

tamtoan
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correct

clarkexo
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okay, So you're not supposed to flip it then? :S

tamtoan
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it's two positive powers 2 and 3..you add..one negative power 4 ..you subtract

clarkexo
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ty

tamtoan
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yw :)