## anonymous 4 years ago help me solve: (a^2)^-5

1. hartnn

$$\huge (x^n)^m=x^{mn}$$ does this help?

2. anonymous

so the answer is a^10?

3. hartnn

2*(-5)=-10 so its a^(-10) ok?

4. anonymous

so I don't flip the exponent and make it positive?

5. hartnn

nopes, not here. you flip the sign of exponent only when you take its reciprocal $$\huge \frac{1}{x^n}=x^{-n}$$

6. anonymous

OHHHHH, okay- that helps. ty!

7. hartnn

welcome ^_^