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clarkexo Group Title

help me solve: (a^2)^-5

  • 2 years ago
  • 2 years ago

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  1. hartnn Group Title
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    \(\huge (x^n)^m=x^{mn}\) does this help?

    • 2 years ago
  2. clarkexo Group Title
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    so the answer is a^10?

    • 2 years ago
  3. hartnn Group Title
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    2*(-5)=-10 so its a^(-10) ok?

    • 2 years ago
  4. clarkexo Group Title
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    so I don't flip the exponent and make it positive?

    • 2 years ago
  5. hartnn Group Title
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    nopes, not here. you flip the sign of exponent only when you take its reciprocal \(\huge \frac{1}{x^n}=x^{-n}\)

    • 2 years ago
  6. clarkexo Group Title
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    OHHHHH, okay- that helps. ty!

    • 2 years ago
  7. hartnn Group Title
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    welcome ^_^

    • 2 years ago
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