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clarkexo

  • 3 years ago

help me solve: (a^2)^-5

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  1. hartnn
    • 3 years ago
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    \(\huge (x^n)^m=x^{mn}\) does this help?

  2. clarkexo
    • 3 years ago
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    so the answer is a^10?

  3. hartnn
    • 3 years ago
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    2*(-5)=-10 so its a^(-10) ok?

  4. clarkexo
    • 3 years ago
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    so I don't flip the exponent and make it positive?

  5. hartnn
    • 3 years ago
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    nopes, not here. you flip the sign of exponent only when you take its reciprocal \(\huge \frac{1}{x^n}=x^{-n}\)

  6. clarkexo
    • 3 years ago
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    OHHHHH, okay- that helps. ty!

  7. hartnn
    • 3 years ago
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    welcome ^_^

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