clarkexo
help me solve: (x^2m)^n



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hartnn
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\(\huge (x^a)^b=x^{ab}\)
same formula again

clarkexo
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Okay so X^2mn?

hartnn
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yes, if your question is \((x^{2m})^n\) then its correct
but is your question \((x^2m)^n\) ??

clarkexo
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No, it's the first one

hartnn
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then \(x^{2mn}\) is correct