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clarkexo

  • 3 years ago

help me solve: (x^2m)^n

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  1. hartnn
    • 3 years ago
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    \(\huge (x^a)^b=x^{ab}\) same formula again

  2. clarkexo
    • 3 years ago
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    Okay- so X^2mn?

  3. hartnn
    • 3 years ago
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    yes, if your question is \((x^{2m})^n\) then its correct but is your question \((x^2m)^n\) ??

  4. clarkexo
    • 3 years ago
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    No, it's the first one

  5. hartnn
    • 3 years ago
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    then \(x^{2mn}\) is correct

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