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clarkexo

  • 3 years ago

solve: (a/5)^-2

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  1. timo86m
    • 3 years ago
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    i think you might be missing an = sign.

  2. Kashan
    • 3 years ago
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    you can write it as (5/a)^2 inverting values will change the sign from negative to positive.. so it will be, 25/a^2

  3. clarkexo
    • 3 years ago
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    nope, its exponents

  4. clarkexo
    • 3 years ago
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    why do you invert the values?

  5. Kashan
    • 3 years ago
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    I told earlier that inverting values will result in sign change.. look after inverting i have changed power sign from negative to positive..

  6. clarkexo
    • 3 years ago
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    I understand that, but I thought you only do that for the reciprocal?

  7. Kashan
    • 3 years ago
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    I did it to make it easier to evaluate.. positive powers are easy to evaluate..

  8. clarkexo
    • 3 years ago
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    okay, so can that apply to all exponent laws?

  9. Kashan
    • 3 years ago
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    yes.. you can apply it any where in mathematics.. :)

  10. clarkexo
    • 3 years ago
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    okay can you also help me with another one i'm about to post

  11. Kashan
    • 3 years ago
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    sure message me the link of that question..

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