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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What are you supposed to do?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
solve the equation or inequality???
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
there is a graph with it and I am so lost.....
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I had ax^2+bx+c=0 and got that one, I think but this????
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
You need to post the entire problem including the graph. The only thing you posted in the general quadratic inequality. Its solution depends entirely upon the values of a, b, and c.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I know right....ok hang on. But I dont no how to post a graph??
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Well then, you could tell what its shape is (I'm assuming it's a parabola), tell if it is concave upward or downward and give its vertex and x intercepts (if any). That would give us a pretty good idea of the problem.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
it is upward, the vertex is 6.5 and 4 and 4 does that help
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the vertex is 6
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
dw:1349043948873:dw
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Does it look like that?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
kinda but the vertex ir right in the middle.....it points upward at 4 on the left and 4 on the right
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So the vertex is on the y axis?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
And it crosses the x axis at (4, 0) and (4,0)?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
dw:1349044244497:dw
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
more like that
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
dw:1349044229220:dw
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Now exactly what does the problem say to do?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
The graph of y=ax^2+bx+c solve each equation . ax^2+bx+c=0 ax^2+bx+c<0 ax^2+bx+c>0
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
There must be more because what you posted doesn't make sense.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I know!! that is exactly as it is posted.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
my options for the second equation are like 7 choices...makes no sense to me??
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Does it say "The graph of y = x*2+bx+c is shown"?
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Ok. Now. I repeat my original request. Please post the problem EXACTLY as shown.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the graph of y=ax^2+bx+c is given below. Solve each equation or inequality. ax^2+bx+c=0 ax^2+bx+c<0 ax^2+bx+c>0
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the vertex is not the 6 it is 30!!!!
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I just seen that......does that help any???
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What are the x intercepts?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
they are the same
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Are you sure?
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
dw:1349045608333:dw
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Then plug into the equation y = a(xh)^2 +k and find the value of a
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Then solve the resulting inequality.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
that is where I am confused....plug what numbers? and plug them in as a????
 2 years ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
(h,k) is the vertex which in your case is (0,32) You are given the x intercepts. Choose one of them, perhaps (4,0). Replace x with 4 and y with 0 and solve for a.
 2 years ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
ok I will try. thx
 2 years ago
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