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Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What are you supposed to do?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
solve the equation or inequality???
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
there is a graph with it and I am so lost.....
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I had ax^2+bx+c=0 and got that one, I think but this????
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
You need to post the entire problem including the graph. The only thing you posted in the general quadratic inequality. Its solution depends entirely upon the values of a, b, and c.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I know right....ok hang on. But I dont no how to post a graph??
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Well then, you could tell what its shape is (I'm assuming it's a parabola), tell if it is concave upward or downward and give its vertex and x intercepts (if any). That would give us a pretty good idea of the problem.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
it is upward, the vertex is 6.5 and 4 and 4 does that help
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the vertex is 6
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
dw:1349043948873:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Does it look like that?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
kinda but the vertex ir right in the middle.....it points upward at 4 on the left and 4 on the right
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
So the vertex is on the y axis?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
And it crosses the x axis at (4, 0) and (4,0)?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
dw:1349044244497:dw
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
more like that
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
dw:1349044229220:dw
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
exactly!!
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Now exactly what does the problem say to do?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
The graph of y=ax^2+bx+c solve each equation . ax^2+bx+c=0 ax^2+bx+c<0 ax^2+bx+c>0
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
There must be more because what you posted doesn't make sense.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I know!! that is exactly as it is posted.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
my options for the second equation are like 7 choices...makes no sense to me??
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Does it say "The graph of y = x*2+bx+c is shown"?
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Ok. Now. I repeat my original request. Please post the problem EXACTLY as shown.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the graph of y=ax^2+bx+c is given below. Solve each equation or inequality. ax^2+bx+c=0 ax^2+bx+c<0 ax^2+bx+c>0
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
the vertex is not the 6 it is 30!!!!
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
I just seen that......does that help any???
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
What are the x intercepts?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
they are the same
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Are you sure?
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
dw:1349045608333:dw
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Then plug into the equation y = a(xh)^2 +k and find the value of a
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
Then solve the resulting inequality.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
that is where I am confused....plug what numbers? and plug them in as a????
 one year ago

Mertsj Group TitleBest ResponseYou've already chosen the best response.0
(h,k) is the vertex which in your case is (0,32) You are given the x intercepts. Choose one of them, perhaps (4,0). Replace x with 4 and y with 0 and solve for a.
 one year ago

byndbtch Group TitleBest ResponseYou've already chosen the best response.0
ok I will try. thx
 one year ago
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