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krypton

  • 3 years ago

find sin(arccsc(20)),where arccsc(theta) is the inverse of csc(theta). please u can also teach me as well,was not in class when the topic was introduced

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  1. alanli123
    • 3 years ago
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    use a calculator?

  2. krypton
    • 3 years ago
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    lol,actually i wanna learn it without calculator :)

  3. krypton
    • 3 years ago
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    calculator cant even do it

  4. alanli123
    • 3 years ago
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    Right so lets get to it. first lets try to simplify arccsc(20). so arccsc is just the inverse function of csc. in csc, you plug in a angle value (domain) and then you obtain a ratio (the range). in an inverse function, this is switched, meaning the domain is now the ratio and the angle value is now the range. so arccsc(20) is asking what angle value will you get when you plug a ratio of 20 into csc. you find that value and plug it into sin

  5. alanli123
    • 3 years ago
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    @krypton

  6. krypton
    • 3 years ago
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    is the answer gonna be 1/20

  7. krypton
    • 3 years ago
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    ?

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