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krypton
Group Title
find sin(arccsc(20)),where arccsc(theta) is the inverse of csc(theta). please u can also teach me as well,was not in class when the topic was introduced
 one year ago
 one year ago
krypton Group Title
find sin(arccsc(20)),where arccsc(theta) is the inverse of csc(theta). please u can also teach me as well,was not in class when the topic was introduced
 one year ago
 one year ago

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alanli123 Group TitleBest ResponseYou've already chosen the best response.0
use a calculator?
 one year ago

krypton Group TitleBest ResponseYou've already chosen the best response.0
lol,actually i wanna learn it without calculator :)
 one year ago

krypton Group TitleBest ResponseYou've already chosen the best response.0
calculator cant even do it
 one year ago

alanli123 Group TitleBest ResponseYou've already chosen the best response.0
Right so lets get to it. first lets try to simplify arccsc(20). so arccsc is just the inverse function of csc. in csc, you plug in a angle value (domain) and then you obtain a ratio (the range). in an inverse function, this is switched, meaning the domain is now the ratio and the angle value is now the range. so arccsc(20) is asking what angle value will you get when you plug a ratio of 20 into csc. you find that value and plug it into sin
 one year ago

alanli123 Group TitleBest ResponseYou've already chosen the best response.0
@krypton
 one year ago

krypton Group TitleBest ResponseYou've already chosen the best response.0
is the answer gonna be 1/20
 one year ago
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