krypton
find sin(arccsc(20)),where arccsc(theta) is the inverse of csc(theta).



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wio
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So let \[\theta = arc\csc(20)\]We have \[\csc(\theta)=\frac{20}{1}\]Or in other words:\[\sin(\theta)=\frac{1}{20}\]Hmmmm.

wio
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What happens when we replace \(\theta\) back with \(arc\csc(20)\)...

wio
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@krypton Making sense?

krypton
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hm.. dont really know the topic,is there any rules for it?

wio
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This is your own question.

krypton
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ok