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krypton

  • 3 years ago

find sin(arccsc(20)),where arccsc(theta) is the inverse of csc(theta).

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  1. wio
    • 3 years ago
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    So let \[\theta = arc\csc(20)\]We have \[\csc(\theta)=\frac{20}{1}\]Or in other words:\[\sin(\theta)=\frac{1}{20}\]Hmmmm.

  2. wio
    • 3 years ago
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    What happens when we replace \(\theta\) back with \(arc\csc(20)\)...

  3. wio
    • 3 years ago
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    @krypton Making sense?

  4. krypton
    • 3 years ago
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    hm.. dont really know the topic,is there any rules for it?

  5. wio
    • 3 years ago
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    This is your own question.

  6. krypton
    • 3 years ago
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    ok

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