Here's the question you clicked on:
akb48
4 + x/2 > 2x How do I solve it? Please and Thank you!
4 + x/2 > 2x multiply both sides by 2 to get 4 + x > 4x bring x over 4> 4x - x 4 >3x 4/3 > x
You multiplied both sides by 2 but still have 4 on the left side?
4 + x/2 > 2x 4 + x/2 >4x/2 4 > 4x/2 - x/2 4 >(4x - x)/2 4 > 3x/2 4*2 > 3x 8 > 3x 8/3 > x
I don't know which one it is either
well i guess the writer will have to verify
@akb48, is it \[\frac{4 +x}{2} > 2x\] or \[4 + \frac{x}{2} > 2x\]
multiply by 2 you get 8 + x > 4x subtracting x 8 > 3x dividing by 3 8/3 > x x < 8/3 \[x \in (-\infty, \frac{ 8 }{ 3 } )\]