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simplify this rational

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\[\frac{ \frac{ 1 }{ x+2 } - \frac{ 1 }{ 2 } }{ x }\]

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Other answers:

@sritama how'd you get that ?
i just added the fractions in numerator.
on taking the LCM \[\frac{ \frac{ 2 - (x +2 )}{ 2(x+2) } }{ x }\] \[\frac{ \frac{ 2 - x -2 }{ 2(x+2) } }{ x }\] \[\frac{ \frac{ - x }{ 2(x+2) } }{ x }\]\[\frac{ -x }{ 2(x-2) } \div x\] \[[\frac{ -x }{ 2(x-2) } \times \frac{ 1 }{ x }]\] \[\frac{ -1 }{ 2(x-2) }\] is the answer, you can simplify further ;)
what do you do from here, sorry i'd like to go step by step, i get confused easily :$
i took the lcm of the numerator, you get it?
ya right, may i go to the next step?
on solving i got numerator = -x/2(x-2) you get it?
after that you can rite this equation similarly as \frac{ -x }{ 2(x-2) } \div x
\[\frac{ -x }{ 2(x-2) } \div x \]you get it?
if i write \[\frac{ 5 }{ 6 } = 5 \div 6 = 5 \times \frac{ 1 }{ 6 }\]
is it correct?
i just wrote it in other way and then -x/x = -1 you get the answer :)
ohh kkk thankyou !

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