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burhan101

  • 2 years ago

simplify this rational

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  1. miteshchvm
    • 2 years ago
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    shoot!

  2. burhan101
    • 2 years ago
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    \[\frac{ \frac{ 1 }{ x+2 } - \frac{ 1 }{ 2 } }{ x }\]

  3. sritama
    • 2 years ago
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    |dw:1349062778744:dw|

  4. burhan101
    • 2 years ago
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    @sritama how'd you get that ?

  5. sritama
    • 2 years ago
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    |dw:1349062838039:dw|

  6. sritama
    • 2 years ago
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    i just added the fractions in numerator.

  7. miteshchvm
    • 2 years ago
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    on taking the LCM \[\frac{ \frac{ 2 - (x +2 )}{ 2(x+2) } }{ x }\] \[\frac{ \frac{ 2 - x -2 }{ 2(x+2) } }{ x }\] \[\frac{ \frac{ - x }{ 2(x+2) } }{ x }\]\[\frac{ -x }{ 2(x-2) } \div x\] \[[\frac{ -x }{ 2(x-2) } \times \frac{ 1 }{ x }]\] \[\frac{ -1 }{ 2(x-2) }\] is the answer, you can simplify further ;)

  8. burhan101
    • 2 years ago
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    |dw:1349063069596:dw|

  9. burhan101
    • 2 years ago
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    what do you do from here, sorry i'd like to go step by step, i get confused easily :$

  10. miteshchvm
    • 2 years ago
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    i took the lcm of the numerator, you get it?

  11. burhan101
    • 2 years ago
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    2(x+2)

  12. miteshchvm
    • 2 years ago
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    ya right, may i go to the next step?

  13. burhan101
    • 2 years ago
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    mhm

  14. miteshchvm
    • 2 years ago
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    on solving i got numerator = -x/2(x-2) you get it?

  15. burhan101
    • 2 years ago
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    yes

  16. miteshchvm
    • 2 years ago
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    after that you can rite this equation similarly as \frac{ -x }{ 2(x-2) } \div x

  17. miteshchvm
    • 2 years ago
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    \[\frac{ -x }{ 2(x-2) } \div x \]you get it?

  18. miteshchvm
    • 2 years ago
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    if i write \[\frac{ 5 }{ 6 } = 5 \div 6 = 5 \times \frac{ 1 }{ 6 }\]

  19. miteshchvm
    • 2 years ago
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    is it correct?

  20. burhan101
    • 2 years ago
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    yeah

  21. miteshchvm
    • 2 years ago
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    i just wrote it in other way and then -x/x = -1 you get the answer :)

  22. burhan101
    • 2 years ago
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    ohh kkk thankyou !

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spraguer (Moderator)
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