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MathSofiya
Group Title
@CliffSedge
I have a table here that I don't quite understand
x 0 1 2 3 4 5
P(x) 0.237 0.396 0.264 0.088 0.015 0.001
x= # of prisons out of 5 on parole who become repeat offenders.
What is P(x)? and why does it add up to 1?
 2 years ago
 2 years ago
MathSofiya Group Title
@CliffSedge I have a table here that I don't quite understand x 0 1 2 3 4 5 P(x) 0.237 0.396 0.264 0.088 0.015 0.001 x= # of prisons out of 5 on parole who become repeat offenders. What is P(x)? and why does it add up to 1?
 2 years ago
 2 years ago

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CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
If they add up to 1, those could be probabilities or proportions.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
Criminal Justice: Parole USA Today reported that approximately 25% of all state prison inmates released on parole become repeat offenders while on parole. Suppose the parole board is examining five prisoners up for parole. Let x= number of prisoners out of five on parole who become repeat offenders. The methods of Section 5.2 can be used to compute the probability assignments for the x distribution.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
so x from 0 to 5 are not "the prisoners"
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
I guess I don't understand what x is...sigh
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
It is a little strangely worded, but it says that x is number out of 5, so x itself is a proportion.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
e.g. x=3 means 3 out of the 5 prisoners up for parole will be repeat offenders.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
\[\frac05\] why is there are chance for repeat offense?
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
probability I mean
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
*shrug* that's just what they are measuring here.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
so when no one is on parole the probability or reoffending is 0.237? That's what they're trying to tell me?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
No, it's saying that for every 5 prisoners out on parole the probability that 0 of them will offend again is 0.237
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
OOHHHHHH....LOL! That makes much more sense! haha
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
5 are out on parole at all time I guess
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
It's just an average 'per 5' basis. There could be 100 parolees, so x=3 means 60 out of 100.
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
one last thing...
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
the probability that 5/5 parolees will reoffend is very slim? highly unlikely?
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
Yeah, 0.001 is pretty low, 1in1,000 chance, but if there are 5,000 parolees, then that's practically a sure thing.
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
(Practically a sure thing to get 5 out of 5,000, not 5,000 out of 5,000 that is)
 2 years ago

MathSofiya Group TitleBest ResponseYou've already chosen the best response.0
Yep makes sense. Thank you once again!
 2 years ago

CliffSedge Group TitleBest ResponseYou've already chosen the best response.1
My pleasure.
 2 years ago
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