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 2 years ago
On a pv diagram, there are constant temperature lines. If the process line is parallel to that of specific volume(that is, constant pressure inside the saturation dome), is there any change in internal energy?
 2 years ago
On a pv diagram, there are constant temperature lines. If the process line is parallel to that of specific volume(that is, constant pressure inside the saturation dome), is there any change in internal energy?

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jrodriguez2315
 2 years ago
Best ResponseYou've already chosen the best response.0dw:1349069900920:dw

Fellowroot
 2 years ago
Best ResponseYou've already chosen the best response.1dw:1349076248710:dw

jrodriguez2315
 2 years ago
Best ResponseYou've already chosen the best response.0Thanks Fellowroot. Exactly what I was looking for... I didn't need help with the problem itself. I just didn't remember one of the concepts.

Fellowroot
 2 years ago
Best ResponseYou've already chosen the best response.1Could you explain it to me how your problem works since I'm really not getting the 1, 2, and 3 on your graph. Glad I could help. I actually took thermodynamics, but i don't know everything.

jrodriguez2315
 2 years ago
Best ResponseYou've already chosen the best response.0Ok. There is a saturated water vapor inside a pistoncylinder that is designed to stop once the volume is .3m^3. The initial pressure is 500kPa, and initial volume is .5m^3. Therefore, P1=P2 (constant pressure). On that pressure line, there is a constant temperature line? Therefore, no change in internal energy.

Fellowroot
 2 years ago
Best ResponseYou've already chosen the best response.1And you are meaning that the constant pressure line is from 1 to 2 right?

jrodriguez2315
 2 years ago
Best ResponseYou've already chosen the best response.0That is correct. Isobaric process from 1 to 2.
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