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On a pv diagram, there are constant temperature lines. If the process line is parallel to that of specific volume(that is, constant pressure inside the saturation dome), is there any change in internal energy?
 one year ago
 one year ago
On a pv diagram, there are constant temperature lines. If the process line is parallel to that of specific volume(that is, constant pressure inside the saturation dome), is there any change in internal energy?
 one year ago
 one year ago

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jrodriguez2315Best ResponseYou've already chosen the best response.0
dw:1349069900920:dw
 one year ago

FellowrootBest ResponseYou've already chosen the best response.1
dw:1349076248710:dw
 one year ago

jrodriguez2315Best ResponseYou've already chosen the best response.0
Thanks Fellowroot. Exactly what I was looking for... I didn't need help with the problem itself. I just didn't remember one of the concepts.
 one year ago

FellowrootBest ResponseYou've already chosen the best response.1
Could you explain it to me how your problem works since I'm really not getting the 1, 2, and 3 on your graph. Glad I could help. I actually took thermodynamics, but i don't know everything.
 one year ago

jrodriguez2315Best ResponseYou've already chosen the best response.0
Ok. There is a saturated water vapor inside a pistoncylinder that is designed to stop once the volume is .3m^3. The initial pressure is 500kPa, and initial volume is .5m^3. Therefore, P1=P2 (constant pressure). On that pressure line, there is a constant temperature line? Therefore, no change in internal energy.
 one year ago

FellowrootBest ResponseYou've already chosen the best response.1
And you are meaning that the constant pressure line is from 1 to 2 right?
 one year ago

jrodriguez2315Best ResponseYou've already chosen the best response.0
That is correct. Isobaric process from 1 to 2.
 one year ago
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