jethro210
determine value h(2a) for function h(x)=x-1/1-x
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jethro210
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i got 2a-1/1-2a=H(x) do i need to do anything else
akash_809
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its (2a-1)/(1-2a) =-1 , so -1 is the answer
UnkleRhaukus
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here are the steps akash_809 has used
\[h(x)=\frac{x-1}{1-x}\]\[h(2a)=\frac{2a-1}{1-2a}\]\[\qquad\quad=\frac{-(1-2a)}{1-2a}\]\[\qquad\quad=\frac{-\cancel{(1-2a)}}{\cancel{1-2a}}\]\[\qquad\quad =-1\]
jethro210
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what if I used A+1 as my x value?
akash_809
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platinum ring again :)
UnkleRhaukus
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ring ring; hello?
akash_809
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@jethro210 it would be same
akash_809
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i.e =-1
UnkleRhaukus
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the function gives the same value for all inputs
(except x=1, which has indeterminate value )
akash_809
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thanks for the medal un(c)kle
UnkleRhaukus
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anytime
akash_809
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@jethro210 u wl always get quick replies due to the pic :) you have used
jethro210
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cool.
jethro210
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