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determine value h(2a) for function h(x)=x-1/1-x

Mathematics
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i got 2a-1/1-2a=H(x) do i need to do anything else
its (2a-1)/(1-2a) =-1 , so -1 is the answer
here are the steps akash_809 has used \[h(x)=\frac{x-1}{1-x}\]\[h(2a)=\frac{2a-1}{1-2a}\]\[\qquad\quad=\frac{-(1-2a)}{1-2a}\]\[\qquad\quad=\frac{-\cancel{(1-2a)}}{\cancel{1-2a}}\]\[\qquad\quad =-1\]

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Other answers:

what if I used A+1 as my x value?
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@jethro210 it would be same
i.e =-1
the function gives the same value for all inputs (except x=1, which has indeterminate value )
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