A community for students. Sign up today

Here's the question you clicked on:

WilsonWorla 3 years ago find all points on the curve y=x^3-3X where the tangent is parallel to the x-axis.

• This Question is Closed
1. lailaiwd

this should be intuitive because tangent parallel to the x-axis implies that its value is 0. And then you find the prime of y, and set it to 0

2. mukushla

tangent is parallel to the x-axis so its slope equals to 0. on the other hand slope of tangent line|dw:1349077584783:dw| equals to derivative of function at the given point

3. Fellowroot

|dw:1349077683740:dw|

4. prawal

find the first derivative... = 3x^2 -3=0 so at x= +1 , -1 the slope of tanget is zero..

5. prawal

the points r (1,-2),(-1,2)

6. Fellowroot
7. prawal

hmm its correct and mine answer too ..

8. hartnn

@WilsonWorla Hi, $$\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile$$ Are you following the explanation, if doubts feel free to ask them.

9. godfreysown

See attached screen shot of my answer, done in Geogegebra

Ask your own question

Sign Up
Find more explanations on OpenStudy
Privacy Policy