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WilsonWorla

  • 3 years ago

find all points on the curve y=x^3-3X where the tangent is parallel to the x-axis.

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  1. lailaiwd
    • 3 years ago
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    this should be intuitive because tangent parallel to the x-axis implies that its value is 0. And then you find the prime of y, and set it to 0

  2. mukushla
    • 3 years ago
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    tangent is parallel to the x-axis so its slope equals to 0. on the other hand slope of tangent line|dw:1349077584783:dw| equals to derivative of function at the given point

  3. Fellowroot
    • 3 years ago
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    |dw:1349077683740:dw|

  4. prawal
    • 3 years ago
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    find the first derivative... = 3x^2 -3=0 so at x= +1 , -1 the slope of tanget is zero..

  5. prawal
    • 3 years ago
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    the points r (1,-2),(-1,2)

  6. prawal
    • 3 years ago
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    hmm its correct and mine answer too ..

  7. hartnn
    • 3 years ago
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    @WilsonWorla Hi, \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\) Are you following the explanation, if doubts feel free to ask them.

  8. godfreysown
    • 3 years ago
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    See attached screen shot of my answer, done in Geogegebra

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