Here's the question you clicked on:
WilsonWorla
find all points on the curve y=x^3-3X where the tangent is parallel to the x-axis.
this should be intuitive because tangent parallel to the x-axis implies that its value is 0. And then you find the prime of y, and set it to 0
tangent is parallel to the x-axis so its slope equals to 0. on the other hand slope of tangent line|dw:1349077584783:dw| equals to derivative of function at the given point
|dw:1349077683740:dw|
find the first derivative... = 3x^2 -3=0 so at x= +1 , -1 the slope of tanget is zero..
the points r (1,-2),(-1,2)
hmm its correct and mine answer too ..
@WilsonWorla Hi, \(\huge \color{red}{\text{Welcome to Open Study}}\ddot\smile\) Are you following the explanation, if doubts feel free to ask them.
See attached screen shot of my answer, done in Geogegebra