ganeshie8
  • ganeshie8
\(11_{11}^2 = ?_{11}\)
Mathematics
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SOLVED
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jamiebookeater
  • jamiebookeater
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mathslover
  • mathslover
What is this? @ganeshie8 can u explain this to me?
anonymous
  • anonymous
\[131_{11}\]
ganeshie8
  • ganeshie8
that looks correct... actually i thought of asking as we move left in base 11, 11^2 becomes 100 ? right ?

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UnkleRhaukus
  • UnkleRhaukus
\[121_{11}\]
ganeshie8
  • ganeshie8
@mathslover subscript means its base 11
UnkleRhaukus
  • UnkleRhaukus
@Zekarias check that
anonymous
  • anonymous
You made algebra mistake I think @UnkleRhaukus
UnkleRhaukus
  • UnkleRhaukus
121+22+1=144
anonymous
  • anonymous
IS A_11=10_10 ??
UnkleRhaukus
  • UnkleRhaukus
yes @sauravshakya
anonymous
  • anonymous
Well then the answer must be less than 121
ganeshie8
  • ganeshie8
im getting 121 too.. but the q i thought of asking was different
UnkleRhaukus
  • UnkleRhaukus
\[11^2_{11}=(11+1)^2=12^2=144\] \[144=121+22+1=121_{11}\]
anonymous
  • anonymous
|dw:1349083712778:dw|
anonymous
  • anonymous
|dw:1349083784134:dw|
ganeshie8
  • ganeshie8
\(11_{10}^2\) = \(100_{11}\) \(11_{10}^3\) = \(1000_{11}\) \(11_{10}^4\) = \(10000_{11}\)
ganeshie8
  • ganeshie8
does that mean the positional value changes as smooth as it changes in base 10 ? therez no advantage of base 10... i use to think we use base 10 coz the progression of positional value is smooth in base 10
UnkleRhaukus
  • UnkleRhaukus
im not sure what you mean by "positional value changes as smooth"
ganeshie8
  • ganeshie8
in base 10, the position value increases in powers of \(10_{10}\), like 10, 100, 1000, 100000 .... . same is happening wid base 11 also, its changing as powers of \(11_{10}\) : 10, 100, 1000, 100000... only if i think in base 11, i see its changing smoothly... else, in base 10 i see it changing as, 11, 121, 1331, 14641...
anonymous
  • anonymous
Since there are 9 digits only....... So I think base is better
anonymous
  • anonymous
I mean base 10
ganeshie8
  • ganeshie8
as long as i think in one base system only, i dont see any problem. all systems look equal to me nw. @sauravshakya 9 digits or 10 digits hw does it matter... u mean 9/10 is easy to remember for us... and since, around 5 digits would be too small, and again, around 20 would be too many to remember... so 10 digits look fairly good to remember so we stuck wid base 10... . looks good rationale to me :)
anonymous
  • anonymous
I mean it is easy to do calculation using base 10..... like division and multiplication
anonymous
  • anonymous
This surely takes time: A^2_11 = ?_11
ganeshie8
  • ganeshie8
|dw:1349086304417:dw|
ganeshie8
  • ganeshie8
surely it doesnt look easy..but thats becoz we didnt learn multiplication tables in base 11, we learned them in base 10. but if we lived in base 11, we would have done it in a snap. i dont think we would have missed anything.. . but im really not sure.. im just inclining towards thinking like this, not fully sure yet .. .
anonymous
  • anonymous
Agreed.
UnkleRhaukus
  • UnkleRhaukus
|dw:1349086853953:dw|

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