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mathslover Group TitleBest ResponseYou've already chosen the best response.0
What is this? @ganeshie8 can u explain this to me?
 one year ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
\[131_{11}\]
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
that looks correct... actually i thought of asking as we move left in base 11, 11^2 becomes 100 ? right ?
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
\[121_{11}\]
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
@mathslover subscript means its base 11
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
@Zekarias check that
 one year ago

Zekarias Group TitleBest ResponseYou've already chosen the best response.1
You made algebra mistake I think @UnkleRhaukus
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
121+22+1=144
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
IS A_11=10_10 ??
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
yes @sauravshakya
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Well then the answer must be less than 121
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
im getting 121 too.. but the q i thought of asking was different
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
\[11^2_{11}=(11+1)^2=12^2=144\] \[144=121+22+1=121_{11}\]
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1349083712778:dw
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
http://openstudy.com/study#/updates/50694b4ce4b0e3061a1d953f
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
dw:1349083784134:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
\(11_{10}^2\) = \(100_{11}\) \(11_{10}^3\) = \(1000_{11}\) \(11_{10}^4\) = \(10000_{11}\)
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
does that mean the positional value changes as smooth as it changes in base 10 ? therez no advantage of base 10... i use to think we use base 10 coz the progression of positional value is smooth in base 10
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
im not sure what you mean by "positional value changes as smooth"
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
in base 10, the position value increases in powers of \(10_{10}\), like 10, 100, 1000, 100000 .... . same is happening wid base 11 also, its changing as powers of \(11_{10}\) : 10, 100, 1000, 100000... only if i think in base 11, i see its changing smoothly... else, in base 10 i see it changing as, 11, 121, 1331, 14641...
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Since there are 9 digits only....... So I think base is better
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
I mean base 10
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
as long as i think in one base system only, i dont see any problem. all systems look equal to me nw. @sauravshakya 9 digits or 10 digits hw does it matter... u mean 9/10 is easy to remember for us... and since, around 5 digits would be too small, and again, around 20 would be too many to remember... so 10 digits look fairly good to remember so we stuck wid base 10... . looks good rationale to me :)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
I mean it is easy to do calculation using base 10..... like division and multiplication
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
This surely takes time: A^2_11 = ?_11
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
dw:1349086304417:dw
 one year ago

ganeshie8 Group TitleBest ResponseYou've already chosen the best response.1
surely it doesnt look easy..but thats becoz we didnt learn multiplication tables in base 11, we learned them in base 10. but if we lived in base 11, we would have done it in a snap. i dont think we would have missed anything.. . but im really not sure.. im just inclining towards thinking like this, not fully sure yet .. .
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Agreed.
 one year ago

UnkleRhaukus Group TitleBest ResponseYou've already chosen the best response.3
dw:1349086853953:dw
 one year ago
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