ganeshie8 3 years ago \(11_{11}^2 = ?_{11}\)

1. mathslover

What is this? @ganeshie8 can u explain this to me?

2. Zekarias

\[131_{11}\]

3. ganeshie8

that looks correct... actually i thought of asking as we move left in base 11, 11^2 becomes 100 ? right ?

4. UnkleRhaukus

\[121_{11}\]

5. ganeshie8

@mathslover subscript means its base 11

6. UnkleRhaukus

@Zekarias check that

7. Zekarias

You made algebra mistake I think @UnkleRhaukus

8. UnkleRhaukus

121+22+1=144

9. sauravshakya

IS A_11=10_10 ??

10. UnkleRhaukus

yes @sauravshakya

11. sauravshakya

Well then the answer must be less than 121

12. ganeshie8

im getting 121 too.. but the q i thought of asking was different

13. UnkleRhaukus

\[11^2_{11}=(11+1)^2=12^2=144\] \[144=121+22+1=121_{11}\]

14. sauravshakya

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15. UnkleRhaukus
16. sauravshakya

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17. ganeshie8

\(11_{10}^2\) = \(100_{11}\) \(11_{10}^3\) = \(1000_{11}\) \(11_{10}^4\) = \(10000_{11}\)

18. ganeshie8

does that mean the positional value changes as smooth as it changes in base 10 ? therez no advantage of base 10... i use to think we use base 10 coz the progression of positional value is smooth in base 10

19. UnkleRhaukus

im not sure what you mean by "positional value changes as smooth"

20. ganeshie8

in base 10, the position value increases in powers of \(10_{10}\), like 10, 100, 1000, 100000 .... . same is happening wid base 11 also, its changing as powers of \(11_{10}\) : 10, 100, 1000, 100000... only if i think in base 11, i see its changing smoothly... else, in base 10 i see it changing as, 11, 121, 1331, 14641...

21. sauravshakya

Since there are 9 digits only....... So I think base is better

22. sauravshakya

I mean base 10

23. ganeshie8

as long as i think in one base system only, i dont see any problem. all systems look equal to me nw. @sauravshakya 9 digits or 10 digits hw does it matter... u mean 9/10 is easy to remember for us... and since, around 5 digits would be too small, and again, around 20 would be too many to remember... so 10 digits look fairly good to remember so we stuck wid base 10... . looks good rationale to me :)

24. sauravshakya

I mean it is easy to do calculation using base 10..... like division and multiplication

25. sauravshakya

This surely takes time: A^2_11 = ?_11

26. ganeshie8

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27. ganeshie8

surely it doesnt look easy..but thats becoz we didnt learn multiplication tables in base 11, we learned them in base 10. but if we lived in base 11, we would have done it in a snap. i dont think we would have missed anything.. . but im really not sure.. im just inclining towards thinking like this, not fully sure yet .. .

28. sauravshakya

Agreed.

29. UnkleRhaukus

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