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What is this? @ganeshie8 can u explain this to me?

\[131_{11}\]

\[121_{11}\]

@mathslover subscript means its base 11

@Zekarias check that

You made algebra mistake I think @UnkleRhaukus

121+22+1=144

IS A_11=10_10 ??

Well then the answer must be less than 121

im getting 121 too.. but the q i thought of asking was different

\[11^2_{11}=(11+1)^2=12^2=144\]
\[144=121+22+1=121_{11}\]

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\(11_{10}^2\) = \(100_{11}\)
\(11_{10}^3\) = \(1000_{11}\)
\(11_{10}^4\) = \(10000_{11}\)

im not sure what you mean by "positional value changes as smooth"

Since there are 9 digits only....... So I think base is better

I mean base 10

I mean it is easy to do calculation using base 10..... like division and multiplication

This surely takes time:
A^2_11 = ?_11

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Agreed.

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