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ganeshie8

\(11_{11}^2 = ?_{11}\)

  • one year ago
  • one year ago

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  1. mathslover
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    What is this? @ganeshie8 can u explain this to me?

    • one year ago
  2. Zekarias
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    \[131_{11}\]

    • one year ago
  3. ganeshie8
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    that looks correct... actually i thought of asking as we move left in base 11, 11^2 becomes 100 ? right ?

    • one year ago
  4. UnkleRhaukus
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    \[121_{11}\]

    • one year ago
  5. ganeshie8
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    @mathslover subscript means its base 11

    • one year ago
  6. UnkleRhaukus
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    @Zekarias check that

    • one year ago
  7. Zekarias
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    You made algebra mistake I think @UnkleRhaukus

    • one year ago
  8. UnkleRhaukus
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    121+22+1=144

    • one year ago
  9. sauravshakya
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    IS A_11=10_10 ??

    • one year ago
  10. UnkleRhaukus
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    yes @sauravshakya

    • one year ago
  11. sauravshakya
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    Well then the answer must be less than 121

    • one year ago
  12. ganeshie8
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    im getting 121 too.. but the q i thought of asking was different

    • one year ago
  13. UnkleRhaukus
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    \[11^2_{11}=(11+1)^2=12^2=144\] \[144=121+22+1=121_{11}\]

    • one year ago
  14. sauravshakya
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    |dw:1349083712778:dw|

    • one year ago
  15. UnkleRhaukus
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    http://openstudy.com/study#/updates/50694b4ce4b0e3061a1d953f

    • one year ago
  16. sauravshakya
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    |dw:1349083784134:dw|

    • one year ago
  17. ganeshie8
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    \(11_{10}^2\) = \(100_{11}\) \(11_{10}^3\) = \(1000_{11}\) \(11_{10}^4\) = \(10000_{11}\)

    • one year ago
  18. ganeshie8
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    does that mean the positional value changes as smooth as it changes in base 10 ? therez no advantage of base 10... i use to think we use base 10 coz the progression of positional value is smooth in base 10

    • one year ago
  19. UnkleRhaukus
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    im not sure what you mean by "positional value changes as smooth"

    • one year ago
  20. ganeshie8
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    in base 10, the position value increases in powers of \(10_{10}\), like 10, 100, 1000, 100000 .... . same is happening wid base 11 also, its changing as powers of \(11_{10}\) : 10, 100, 1000, 100000... only if i think in base 11, i see its changing smoothly... else, in base 10 i see it changing as, 11, 121, 1331, 14641...

    • one year ago
  21. sauravshakya
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    Since there are 9 digits only....... So I think base is better

    • one year ago
  22. sauravshakya
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    I mean base 10

    • one year ago
  23. ganeshie8
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    as long as i think in one base system only, i dont see any problem. all systems look equal to me nw. @sauravshakya 9 digits or 10 digits hw does it matter... u mean 9/10 is easy to remember for us... and since, around 5 digits would be too small, and again, around 20 would be too many to remember... so 10 digits look fairly good to remember so we stuck wid base 10... . looks good rationale to me :)

    • one year ago
  24. sauravshakya
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    I mean it is easy to do calculation using base 10..... like division and multiplication

    • one year ago
  25. sauravshakya
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    This surely takes time: A^2_11 = ?_11

    • one year ago
  26. ganeshie8
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    |dw:1349086304417:dw|

    • one year ago
  27. ganeshie8
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    surely it doesnt look easy..but thats becoz we didnt learn multiplication tables in base 11, we learned them in base 10. but if we lived in base 11, we would have done it in a snap. i dont think we would have missed anything.. . but im really not sure.. im just inclining towards thinking like this, not fully sure yet .. .

    • one year ago
  28. sauravshakya
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    Agreed.

    • one year ago
  29. UnkleRhaukus
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    |dw:1349086853953:dw|

    • one year ago
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