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shivraj Group Title

Given f(x)=x^2-1 and g(x)=x+1, find (fog)(x)?

  • 2 years ago
  • 2 years ago

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  1. sauravshakya Group Title
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    (fog)(x) = f(g(x)) = f(x+1)

    • 2 years ago
  2. sauravshakya Group Title
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    @shivraj u got what I did??????

    • 2 years ago
  3. shivraj Group Title
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    no sir

    • 2 years ago
  4. miteshchvm Group Title
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    that means you need to put x= x + 1 in f(x)

    • 2 years ago
  5. sauravshakya Group Title
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    Yep: (fog)=f(g(x))

    • 2 years ago
  6. sauravshakya Group Title
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    Now, substitute there g(x)

    • 2 years ago
  7. miteshchvm Group Title
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    suppose f(1) = 0 f(x) = x^2 - 1 f[g(x)] = (x+1)^2 - 1

    • 2 years ago
  8. shivraj Group Title
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    ok

    • 2 years ago
  9. miteshchvm Group Title
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    you got it? @shivraj

    • 2 years ago
  10. shivraj Group Title
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    yep

    • 2 years ago
  11. godfreysown Group Title
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    if \[f(x)=x^2-1\ and \ g(x)=x+1, \\ \ then \ (fog)'(x)=\ (by \ product \ rule)\ u'v+u'v, \\where\ u=f(x); \ v=g(x) \\ \therefore\ (x^2-1)(1)+(2x)(x+1)=\\x^2-1+2x^2+2x=\\3x^2+2x-1=\\(3x-1)(x+1) \]

    • 2 years ago
  12. shivraj Group Title
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    thnks godfreysown

    • 2 years ago
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