Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
← 55 members online
 0 viewing

This Question is Closed

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
(fog)(x) = f(g(x)) = f(x+1)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
@shivraj u got what I did??????
 one year ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
that means you need to put x= x + 1 in f(x)
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Yep: (fog)=f(g(x))
 one year ago

sauravshakya Group TitleBest ResponseYou've already chosen the best response.1
Now, substitute there g(x)
 one year ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
suppose f(1) = 0 f(x) = x^2  1 f[g(x)] = (x+1)^2  1
 one year ago

miteshchvm Group TitleBest ResponseYou've already chosen the best response.0
you got it? @shivraj
 one year ago

godfreysown Group TitleBest ResponseYou've already chosen the best response.1
if \[f(x)=x^21\ and \ g(x)=x+1, \\ \ then \ (fog)'(x)=\ (by \ product \ rule)\ u'v+u'v, \\where\ u=f(x); \ v=g(x) \\ \therefore\ (x^21)(1)+(2x)(x+1)=\\x^21+2x^2+2x=\\3x^2+2x1=\\(3x1)(x+1) \]
 one year ago

shivraj Group TitleBest ResponseYou've already chosen the best response.0
thnks godfreysown
 one year ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.