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sauravshakyaBest ResponseYou've already chosen the best response.1
(fog)(x) = f(g(x)) = f(x+1)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
@shivraj u got what I did??????
 one year ago

miteshchvmBest ResponseYou've already chosen the best response.0
that means you need to put x= x + 1 in f(x)
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Yep: (fog)=f(g(x))
 one year ago

sauravshakyaBest ResponseYou've already chosen the best response.1
Now, substitute there g(x)
 one year ago

miteshchvmBest ResponseYou've already chosen the best response.0
suppose f(1) = 0 f(x) = x^2  1 f[g(x)] = (x+1)^2  1
 one year ago

miteshchvmBest ResponseYou've already chosen the best response.0
you got it? @shivraj
 one year ago

godfreysownBest ResponseYou've already chosen the best response.1
if \[f(x)=x^21\ and \ g(x)=x+1, \\ \ then \ (fog)'(x)=\ (by \ product \ rule)\ u'v+u'v, \\where\ u=f(x); \ v=g(x) \\ \therefore\ (x^21)(1)+(2x)(x+1)=\\x^21+2x^2+2x=\\3x^2+2x1=\\(3x1)(x+1) \]
 one year ago
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