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Hello could someone please check this problem that I did?

Mathematics
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\[take the intergral of \sqrt{\frac{ 2 }{ x }}\]
My answer is \[2\sqrt{2x}\]
\[\large{\int \sqrt{\frac{2}{x}}}\] Like this?

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Other answers:

yes
sorry I am new to this website I could not figure out how to draw the integral sign.
\[\large{\int \frac{\sqrt{2}}{\sqrt{x}}}\] \[\large{\int \sqrt{2}x^{-\frac{1}{2}}}\] \[\large{\sqrt{2}\times \frac{x^{\frac{-1}{2}+1}}{\frac{-1}{2} +1}}}{\]
Can you solve further ?
i) You were right :) ii) Don't forget to put +C there... i.e integration constant.
I have solved it already and I got \[2\sqrt{2x}\] as the answer
And for integration use : \int
oh thank you
No problem , good work though but that constant is the most important in integration. Also , \[\huge{\color{blue}{\mathbb{Welcome}}\space \color{red}{\mathsf{To}} \space \color{orange}{\frak{OpenStudy}}}\]
Best of luck for your journey in helping others and being helped by others, here in OpenStudy.

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