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Anhina07

  • 3 years ago

Hello could someone please check this problem that I did?

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  1. Anhina07
    • 3 years ago
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    \[take the intergral of \sqrt{\frac{ 2 }{ x }}\]

  2. Anhina07
    • 3 years ago
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    My answer is \[2\sqrt{2x}\]

  3. mathslover
    • 3 years ago
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    \[\large{\int \sqrt{\frac{2}{x}}}\] Like this?

  4. Anhina07
    • 3 years ago
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    yes

  5. Anhina07
    • 3 years ago
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    sorry I am new to this website I could not figure out how to draw the integral sign.

  6. mathslover
    • 3 years ago
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    \[\large{\int \frac{\sqrt{2}}{\sqrt{x}}}\] \[\large{\int \sqrt{2}x^{-\frac{1}{2}}}\] \[\large{\sqrt{2}\times \frac{x^{\frac{-1}{2}+1}}{\frac{-1}{2} +1}}}{\]

  7. mathslover
    • 3 years ago
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    Can you solve further ?

  8. mathslover
    • 3 years ago
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    i) You were right :) ii) Don't forget to put +C there... i.e integration constant.

  9. Anhina07
    • 3 years ago
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    I have solved it already and I got \[2\sqrt{2x}\] as the answer

  10. mathslover
    • 3 years ago
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    And for integration use : \int

  11. Anhina07
    • 3 years ago
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    oh thank you

  12. mathslover
    • 3 years ago
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    No problem , good work though but that constant is the most important in integration. Also , \[\huge{\color{blue}{\mathbb{Welcome}}\space \color{red}{\mathsf{To}} \space \color{orange}{\frak{OpenStudy}}}\]

  13. mathslover
    • 3 years ago
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    Best of luck for your journey in helping others and being helped by others, here in OpenStudy.

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