experimentX
  • experimentX
What's this supposed to mean We shall say that an n-digit number is pandigital if it makes use of all the digits 1 to n exactly once; for example, the 5-digit number, 15234, is 1 through 5 pandigital. The product 7254 is unusual, as the identity, 39x186 = 7254, containing multiplicand, multiplier, and product is 1 through 9 pandigital. Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigital. HINT: Some products can be obtained in more than one way so be sure to only include it once in your sum.
Mathematics
  • Stacey Warren - Expert brainly.com
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SOLVED
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chestercat
  • chestercat
I got my questions answered at brainly.com in under 10 minutes. Go to brainly.com now for free help!
experimentX
  • experimentX
the list seems to be 12 483 5796 18 297 5346 42 138 5796 27 198 5346 28 157 4396 39 186 7254 48 159 7632 2 1793 3586 2 4178 8356 2 4358 8716 2 3459 6918 2 3479 6958 2 4659 9318 2 4569 9138 2 4769 9538 2 4679 9358 3 1942 5826 3 2615 7845 3 1625 4875 3 2915 8745 3 2618 7854 3 2918 8754 3 1928 5784 3 1594 4782 4 1732 6928 4 1593 6372 4 1963 7852 4 1738 6952 4 1958 7832 4 2379 9516 6 1432 8592 6 1572 9432 6 1573 9438 7 1235 8645 7 1364 9548
experimentX
  • experimentX
the sum of unique product seems to be 247882
experimentX
  • experimentX
am i missing something?

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cwrw238
  • cwrw238
well there are no examples where multiplier is 8 or 9
experimentX
  • experimentX
I tried all ... couldn't find one.
experimentX
  • experimentX
What's this supposed to mean "Find the sum of all products whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigita"
anonymous
  • anonymous
was the list already provided?
anonymous
  • anonymous
I think it means to add 5796+5346+5796+...
anonymous
  • anonymous
And I dont think all the listed numbers are correct
experimentX
  • experimentX
the list was not provided. I wrote a program to compute the list.
experimentX
  • experimentX
i added up unique values 5796+5346+5796+... = 247882
experimentX
  • experimentX
http://projecteuler.net/problem=32
anonymous
  • anonymous
if the list was already provided, then all you need to you to need first find those number whose multiplicand/multiplier/product identity can be written as a 1 through 9 pandigita. For example 12*483=5796 is a 1 through 9 pandigita (because you can find all digit 1 to 9 in that). But another entry in the list 2*1793=3586 is not a 1 through 9 pandigita (there is no 4). So filter out the 1 through 9 pandigita first. And then sum them up.
anonymous
  • anonymous
oh i see. but the list isn't correct. there are entries which can't be called a 1 through 9 pandigita - i think!
experimentX
  • experimentX
*pandigital looks like it i didn't check it manually.
experimentX
  • experimentX
looks like in need to edit my program.
anonymous
  • anonymous
oh right! "pandigital"...i copied the word! =)
anonymous
  • anonymous
yes, you do!
experimentX
  • experimentX
this looks final 12 483 5796 18 297 5346 42 138 5796 27 198 5346 28 157 4396 39 186 7254 48 159 7632 4 1963 7852 4 1738 6952 -------------------------- sum = 45228
experimentX
  • experimentX
Bingo!! help each other's with medals!!
anonymous
  • anonymous
lol! finally!! yeah, that seems right!
anonymous
  • anonymous
@experimentX u use which programming language to write progrmas
experimentX
  • experimentX
nowdays i'm using matlab + mathematica ... I'm planning to learn python. besides that i know bunch of other languges.
experimentX
  • experimentX
better learn python ... it's serves multipurpose.
anonymous
  • anonymous
Oh ya......... I have seen my friends writting program using python.... That looks good.
experimentX
  • experimentX
once you learn one language ... rest of language have similar structure.
anonymous
  • anonymous
Well i know as u know Q-basic that we learn at school...... and can also use Visual Basic....... But python looks very different.
experimentX
  • experimentX
once you get your hands on it ... probably programming python is lot faster than those in Basic or VB
anonymous
  • anonymous
Well thanx I will try it.

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