anonymous
  • anonymous
s=1-1/3+1/9-...
Mathematics
chestercat
  • chestercat
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RadEn
  • RadEn
use formula : s= a/(1-r) with a=first term r=ratio=u2/u1=u3/u2
anonymous
  • anonymous
huh?
anonymous
  • anonymous
its a geometric progression with contant ratio(r)=-1/3 and its first term(a) is 1 hence we can use a formula for the sum of this g.p. as a(1-r)

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RadEn
  • RadEn
ok, a=1 and r=(-1/3)/1 = -1/3 plug in a=1 and r=-1/3 to that formula!
anonymous
  • anonymous
soooo its 3/4??
anonymous
  • anonymous
yup
anonymous
  • anonymous
sorry i did a mistake in the formula it will be a/(1-r)
anonymous
  • anonymous
do u do it the same way when the question is 4/3+2/3+1/3...
RadEn
  • RadEn
yea, that's right.
anonymous
  • anonymous
yes here the ratio(r) is 1/2 ..
anonymous
  • anonymous
k thx
RadEn
  • RadEn
oke, what's answer do u get ?

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