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Decart
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how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?
 2 years ago
 2 years ago
Decart Group Title
how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?
 2 years ago
 2 years ago

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HELLSGUARDIAN Group TitleBest ResponseYou've already chosen the best response.1
it will be 0.5kx^2 where k=9.17&x=0.133
 2 years ago

Yahoo! Group TitleBest ResponseYou've already chosen the best response.0
\[W = F * D\]
 2 years ago

valentin68 Group TitleBest ResponseYou've already chosen the best response.0
By definition the work needed to stretch a sping having elastic constant k with the dispăplacement x is equal to the elastic potential energy variation W =k*x^2/2 = 9.17*0.133*0.133/2 =0.081 J
 2 years ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
This problem is in the Energy Conservation in Oscilatory Motion section of the textbook why is that?
 2 years ago

HELLSGUARDIAN Group TitleBest ResponseYou've already chosen the best response.1
this is because the work we do on the spring gets converted to the potential energy of the spring & gets conserved..and can be used when needed:)
 2 years ago

009infinity Group TitleBest ResponseYou've already chosen the best response.0
.16220j
 2 years ago

avijit Group TitleBest ResponseYou've already chosen the best response.0
i agree vth 009infi...
 2 years ago

HELLSGUARDIAN Group TitleBest ResponseYou've already chosen the best response.1
@Decart you got my point???
 2 years ago

Decart Group TitleBest ResponseYou've already chosen the best response.0
Yes the book likes to throw you of course work was chapter 7 so I did not expect to see it here.'
 2 years ago

009infinity Group TitleBest ResponseYou've already chosen the best response.0
but how can it be so 1/2mv^2 is for energy@valentin68
 2 years ago
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