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anonymous
 3 years ago
how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?
anonymous
 3 years ago
how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?

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anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0it will be 0.5kx^2 where k=9.17&x=0.133

valentin68
 3 years ago
Best ResponseYou've already chosen the best response.0By definition the work needed to stretch a sping having elastic constant k with the dispăplacement x is equal to the elastic potential energy variation W =k*x^2/2 = 9.17*0.133*0.133/2 =0.081 J

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0This problem is in the Energy Conservation in Oscilatory Motion section of the textbook why is that?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0this is because the work we do on the spring gets converted to the potential energy of the spring & gets conserved..and can be used when needed:)

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i agree vth 009infi...

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@Decart you got my point???

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Yes the book likes to throw you of course work was chapter 7 so I did not expect to see it here.'

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0but how can it be so 1/2mv^2 is for energy@valentin68
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