A community for students.
Here's the question you clicked on:
 0 viewing
Decart
 3 years ago
how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?
Decart
 3 years ago
how much work is required to stretch a spring 0.133 m if its force constant is 9.17N/m?

This Question is Closed

HELLSGUARDIAN
 3 years ago
Best ResponseYou've already chosen the best response.1it will be 0.5kx^2 where k=9.17&x=0.133

valentin68
 3 years ago
Best ResponseYou've already chosen the best response.0By definition the work needed to stretch a sping having elastic constant k with the dispăplacement x is equal to the elastic potential energy variation W =k*x^2/2 = 9.17*0.133*0.133/2 =0.081 J

Decart
 3 years ago
Best ResponseYou've already chosen the best response.0This problem is in the Energy Conservation in Oscilatory Motion section of the textbook why is that?

HELLSGUARDIAN
 3 years ago
Best ResponseYou've already chosen the best response.1this is because the work we do on the spring gets converted to the potential energy of the spring & gets conserved..and can be used when needed:)

HELLSGUARDIAN
 3 years ago
Best ResponseYou've already chosen the best response.1@Decart you got my point???

Decart
 3 years ago
Best ResponseYou've already chosen the best response.0Yes the book likes to throw you of course work was chapter 7 so I did not expect to see it here.'

009infinity
 3 years ago
Best ResponseYou've already chosen the best response.0but how can it be so 1/2mv^2 is for energy@valentin68
Ask your own question
Sign UpFind more explanations on OpenStudy
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.