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anonymous
 4 years ago
identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)
anonymous
 4 years ago
identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)

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aaronq
 4 years ago
Best ResponseYou've already chosen the best response.1SnO2 > Sn Sn oxidation states: +4 > 0 So Sn is being reduced, thus SnO2 is the oxidizing agent.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0thank you! one more question, how did you get the oxidation state on SnO2 as +4?

aaronq
 4 years ago
Best ResponseYou've already chosen the best response.1there are guidelines (look these up on google) to appoint oxidation states to certain elements according to their place on the periodic table.. per say, K and H are always +1, O is always 2, etc... then you add up the number to equal zero, unless they have a charge.. eg. NO ... since O is always 2, N must be +2. CO2 .. O is 2 but there are two of them, so 4, therefore C is +4. HCl.. H is +1, Cl must be 1 NH4+ .. H is +1, positive charge account for one H.. so you have +3, N is3.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0okay I understand it now thank you so much!
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