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chelseeirene
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identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)
 one year ago
 one year ago
chelseeirene Group Title
identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)
 one year ago
 one year ago

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aaronq Group TitleBest ResponseYou've already chosen the best response.1
SnO2 > Sn Sn oxidation states: +4 > 0 So Sn is being reduced, thus SnO2 is the oxidizing agent.
 one year ago

chelseeirene Group TitleBest ResponseYou've already chosen the best response.0
thank you! one more question, how did you get the oxidation state on SnO2 as +4?
 one year ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
there are guidelines (look these up on google) to appoint oxidation states to certain elements according to their place on the periodic table.. per say, K and H are always +1, O is always 2, etc... then you add up the number to equal zero, unless they have a charge.. eg. NO ... since O is always 2, N must be +2. CO2 .. O is 2 but there are two of them, so 4, therefore C is +4. HCl.. H is +1, Cl must be 1 NH4+ .. H is +1, positive charge account for one H.. so you have +3, N is3.
 one year ago

chelseeirene Group TitleBest ResponseYou've already chosen the best response.0
okay I understand it now thank you so much!
 one year ago
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