Got Homework?
Connect with other students for help. It's a free community.
Here's the question you clicked on:
 0 viewing
chelseeirene
Group Title
identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)
 2 years ago
 2 years ago
chelseeirene Group Title
identify the oxidizing agent in the reaction SnO2(s) + 2C(s) > Sn(l) + 2CO(g)
 2 years ago
 2 years ago

This Question is Closed

aaronq Group TitleBest ResponseYou've already chosen the best response.1
SnO2 > Sn Sn oxidation states: +4 > 0 So Sn is being reduced, thus SnO2 is the oxidizing agent.
 2 years ago

chelseeirene Group TitleBest ResponseYou've already chosen the best response.0
thank you! one more question, how did you get the oxidation state on SnO2 as +4?
 2 years ago

aaronq Group TitleBest ResponseYou've already chosen the best response.1
there are guidelines (look these up on google) to appoint oxidation states to certain elements according to their place on the periodic table.. per say, K and H are always +1, O is always 2, etc... then you add up the number to equal zero, unless they have a charge.. eg. NO ... since O is always 2, N must be +2. CO2 .. O is 2 but there are two of them, so 4, therefore C is +4. HCl.. H is +1, Cl must be 1 NH4+ .. H is +1, positive charge account for one H.. so you have +3, N is3.
 2 years ago

chelseeirene Group TitleBest ResponseYou've already chosen the best response.0
okay I understand it now thank you so much!
 2 years ago
See more questions >>>
Your question is ready. Sign up for free to start getting answers.
spraguer
(Moderator)
5
→ View Detailed Profile
is replying to Can someone tell me what button the professor is hitting...
23
 Teamwork 19 Teammate
 Problem Solving 19 Hero
 Engagement 19 Mad Hatter
 You have blocked this person.
 ✔ You're a fan Checking fan status...
Thanks for being so helpful in mathematics. If you are getting quality help, make sure you spread the word about OpenStudy.