dydlf
8(9^x)+3(6^x)81(4^x)=0 help pleaaase :D



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mukushla
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divide by 6^x

klimenkov
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Or by \(4^x\)

mukushla
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\[8\times(\frac{9}{6})^x+381\times(\frac{4}{6})^x=0\]\[8\times(\frac{3}{2})^x+381\times(\frac{2}{3})^x=0\]and let \[t=(\frac{3}{2})^x\]

mukushla
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make a quadratic in terms of t and solve for t

mukushla
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and also u will have a similar process with what klimenkov said