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dydlf

  • 3 years ago

8(9^x)+3(6^x)-81(4^x)=0 help pleaaase :D

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  1. mukushla
    • 3 years ago
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    divide by 6^x

  2. klimenkov
    • 3 years ago
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    Or by \(4^x\)

  3. mukushla
    • 3 years ago
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    \[8\times(\frac{9}{6})^x+3-81\times(\frac{4}{6})^x=0\]\[8\times(\frac{3}{2})^x+3-81\times(\frac{2}{3})^x=0\]and let \[t=(\frac{3}{2})^x\]

  4. mukushla
    • 3 years ago
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    make a quadratic in terms of t and solve for t

  5. mukushla
    • 3 years ago
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    and also u will have a similar process with what klimenkov said

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