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mathslover
 3 years ago
A particle is projected with speed \(\sqrt{3} i\cap + j\cap +k\cap\) from the origin. If the highest point of trajectory , the velocity vector makes and angle \(\theta\) with naxis, then find \(\tan \theta\)
mathslover
 3 years ago
A particle is projected with speed \(\sqrt{3} i\cap + j\cap +k\cap\) from the origin. If the highest point of trajectory , the velocity vector makes and angle \(\theta\) with naxis, then find \(\tan \theta\)

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mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1I don't know how to represent i cap

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1dw:1349108807115:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0Three CoorDinates...hm......if it is Two Cordinate tanx = vy/vx @highest point of trajectory vertical component of velocity is 0

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1\[u\sin \theta = 0\]

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0if this is TwoCordinate then usinx =0........Since it is a Three Coordinate...) i dont thhink...so...and i have nt studied....Three Coordinate Plane...

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1hmn no problem. @experimentX @sauravshakya @helder_edwin any ideas?

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1@Jemurray3 @mukushla @ghazi @ganeshie8

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@mathslover what does n axis refer to? this is supposed to be a three dimensional coordinate system

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0and theta= 30 degrees

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Well the question dont tells this .... I am also confused , also in starting it is written : Treat vertically upward as Kdw:1349109611966:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0i mean \[\tan \theta = \frac{ 1 }{ \sqrt3 }\]

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1You're correct @ghazi but HOW?

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0see if you consider a three dimensional system check out the spherical coordinate system on google you'll find theta is the angle between x and y axis now \[\tan \theta= \frac{ y }{ x }=\frac{ 1 }{ \sqrt3 }\] x and y are the intercepts

mathslover
 3 years ago
Best ResponseYou've already chosen the best response.1Oh very easy it was, I feel it now. Thanks a ton @ghazi

amistre64
 3 years ago
Best ResponseYou've already chosen the best response.1this is what i was thinking dw:1349110013381:dw

anonymous
 3 years ago
Best ResponseYou've already chosen the best response.0@amistre64 nice work, @mathslover this is what i was talking about .....
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