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hi krypton.. you still there? I think i might be able to help if you are

yea dear

consider the derivative of arctan^2(u) where u=sqrt x and use the chain rule...

u mean?

what is the derivative of (f(x))^2?

it would be something like 2(f(x))times f prime of x

in this case, f(u)=tan-1u, where u=sqrt of x. does this make sense?

questions are good here. the more you ask, the more i can help... :)

yea

so what is the derivative of tan-1u?

you can give me your best guess if you like

hmm actually i wasnt in the class when the topic was taught, but i thinkis =1/srt 1-x^2?

sorry 1/1+x^2

so thats the answer?

no, we have a power of tan-1. so the answer is 2(tan-1(sqrtx))(1/(1+x))1/2sqrtx

is that making sense to you?

still there?

ok

so what will be my final answer?

it is above

can u help me with one other questionÃ‰

if i can, i would be happy to

ok. any ideas where to start?

hmm i dont have an idea

hmm..no idea lol

dont know anytin about the topic yet

it is ok... remember the quotient rule d(f/g)/dx=[(fprime)g-(gprime)f]/g^2?

in this case the numerator is f=sqrt(1-x^2) +1 and g=2cos-1(x)

do you know the product rule?

yes

phew...!! i am so glad. i thought for a sec we were outta options. lol

ok

look at f(x)=sqrt(1-x^2)+1 and g(x)=(2cos-1(x))^-1. does this make sense?

hahaha i can still
remember my calculus 1, this calculus 2

yes it does

just algebra after you get the derivatives.

so i should get the derivative of each of them separatelyÃ‰