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anonymous
 4 years ago
inverse and inverse trignometric functions
find d/dx(arctan^2(sqrt(x))
anonymous
 4 years ago
inverse and inverse trignometric functions find d/dx(arctan^2(sqrt(x))

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anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hi krypton.. you still there? I think i might be able to help if you are

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0consider the derivative of arctan^2(u) where u=sqrt x and use the chain rule...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0sorry. let's start with the derivative of (tan1u)^2. what is the derivative of this little beastie. lol there we go...

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0what is the derivative of (f(x))^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it would be something like 2(f(x))times f prime of x

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in this case, f(u)=tan1u, where u=sqrt of x. does this make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0questions are good here. the more you ask, the more i can help... :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what is the derivative of tan1u?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0you can give me your best guess if you like

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm actually i wasnt in the class when the topic was taught, but i thinkis =1/srt 1x^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0that is totally correct. :) now replace the x with u so that we can use the chain rule where u=1/sqrtx.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0no, we have a power of tan1. so the answer is 2(tan1(sqrtx))(1/(1+x))1/2sqrtx

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0is that making sense to you?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so what will be my final answer?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0can u help me with one other questionÉ

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0if i can, i would be happy to

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0find \[find d/dx (\sqrt{1x ^{2}}+1/2\cos ^{1}(x) and verify whether or \not this is equal \to (2x+1)d/dx \sin ^{1}(x)\]

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok. any ideas where to start?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0oh... and i didnt get anything beyond the arrow... sorry... but i think i have enough to figure it out. :)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hmm i dont have an idea

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0ok, well, it is a rather large function, but it is a quotient (hint). So where might we start with this lovely little thing?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0dont know anytin about the topic yet

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0it is ok... remember the quotient rule d(f/g)/dx=[(fprime)g(gprime)f]/g^2?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0in this case the numerator is f=sqrt(1x^2) +1 and g=2cos1(x)

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0do you know the product rule?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0phew...!! i am so glad. i thought for a sec we were outta options. lol

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0look at f(x)=sqrt(1x^2)+1 and g(x)=(2cos1(x))^1. does this make sense?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0hahaha i can still remember my calculus 1, this calculus 2

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0glad to hear it... calc I is totally needed here... good, it makes sense. now we need fprime and gprime and i think you are pretty much homefree. so what is fprime and what is gprime?

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0just algebra after you get the derivatives.

anonymous
 4 years ago
Best ResponseYou've already chosen the best response.0so i should get the derivative of each of them separatelyÉ
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